Q. \( (x-4)(2x^2+5x-3) \)
Answer
Use distributive law (multiply each term of the quadratic by x and by −4):
\[
(x-4)(2x^2+5x-3)=x(2x^2+5x-3)-4(2x^2+5x-3)
\]
\[
=2x^3+5x^2-3x-8x^2-20x+12
\]
\[
=2x^3-3x^2-23x+12.
\]
Final result: \(\;2x^3-3x^2-23x+12.\)
Detailed Explanation
Problem: Multiply and simplify \( (x-4)(2x^2+5x-3) \).
-
Distribute \(x\) across the trinomial:
\(x\cdot(2x^2+5x-3)=2x^3+5x^2-3x\). -
Distribute \(-4\) across the trinomial:
\(-4\cdot(2x^2+5x-3)=-8x^2-20x+12\). -
Add the results and combine like terms:
\[
(2x^3+5x^2-3x)+(-8x^2-20x+12)
=2x^3+(5x^2-8x^2)+(-3x-20x)+12
=2x^3-3x^2-23x+12.
\]
Final answer: \(\displaystyle 2x^3-3x^2-23x+12\)
See full solution
FAQs
Q How do I expand \( (x-4)(2x^2+5x-3) \)?
A Multiply and combine like terms: \(x(2x^2+5x-3)-4(2x^2+5x-3)=2x^3-3x^2-23x+12\).
Q How do I factor \(2x^2+5x-3\) and factor the whole expression completely?
A Factor the quadratic: \(2x^2+5x-3=(2x-1)(x+3)\). So the full factorization is \((x-4)(2x-1)(x+3)\).
Q What are the zeros / x-intercepts of the polynomial?
A Set each factor to zero: \(x=4,\; x=\tfrac{1}{2},\; x=-3\).
Q What is the degree and leading coefficient of the expanded polynomial?
A Degree is 3 (cubic). Leading coefficient is 2, so the polynomial is \(2x^3-3x^2-23x+12\).
Q What is the y-intercept?
A Evaluate at \(x=0\): \(y=12\). So the y-intercept is \((0,12)\).
Q What is the end behavior of the graph?
A As \(x\to\infty\), \(f(x)\to\infty\); as \(x\to-\infty\), \(f(x)\to-\infty\). (Odd degree with positive leading coefficient.)
Q Can I use synthetic division with \(x-4\)?
A Yes. Synthetic division by 4 on \(2x^3-3x^2-23x+12\) gives quotient \(2x^2+5x-3\) and remainder 0, confirming \(x-4\) is a factor.
Q What are the multiplicities of the roots?
A Each root \(4,\tfrac{1}{2},-3\) has multiplicity 1, so the graph crosses the x-axis at each zero.
Q How many turning points can the graph have?
A A cubic can have up to 2 turning points (local max and min). Their exact locations require calculus or solving the derivative \(6x^2-6x-23\).
Q What is the domain of the polynomial function?
A The domain is all real numbers, \(\mathbb{R}\); polynomials are defined for every real \(x\).
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