Q. \(7 – 3 + 6 + x\)

Answer

Combine constants: \(7-3+6=10\), so the expression simplifies to \(10+x\).

Detailed Explanation

  1. Identify the terms.

    The expression is \(7 – 3 + 6 + x\). The terms are the numbers 7, −3, 6 (constants) and the symbol \(x\) (a variable). You can only combine like terms: constants with constants, variables with the same variable.

  2. Separate constants from the variable.

    Group the constants together and leave the variable term separate: \((7 – 3 + 6) + x\).

  3. Compute the constants step by step.

    First compute \(7 – 3\):

    \(7 – 3 = 4\).

    Then add the remaining constant \(6\):

    \(4 + 6 = 10\).

  4. Write the simplified expression.

    Replace the constants by their sum and keep the variable term: \(10 + x\).

  5. Optional reorder (commutative property of addition).

    You can also write the final result as \(x + 10\); both represent the same expression.

Final simplified form: \(10 + x\)

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FAQs

What is the simplified form of \(7-3+6+x\)?

Combine the numbers: \(7-3+6 = 10\). The simplified form is \(10+x\), which is usually written as \(x+10\).

What order of operations applies here?

Use left-to-right for addition and subtraction (same precedence). So do \(7-3=4\), then \(4+6=10\), then append \(+x\). No parentheses or exponents change the steps.

Can I rearrange the terms?

Yes. Addition is commutative, so \(7-3+6+x = x+10\). Treat subtraction as adding a negative: \(7+(-3)+6+x\), then reorder and combine.

How do I combine like terms?

Constants combine to one constant: \(7-3+6 = 10\). The variable term \(x\) is different, so the result is \(x+10\). Like terms share the same variable and exponent.

How do I evaluate the expression for a given \(x\)?

Substitute the value into \(x+10\). Example: if \(x=2\), then \(2+10=12\). If \(x=-5\), then \(-5+10=5\).

Can this expression be solved for \(x\)?

Can this expression be solved for \(x\)?

How do negative values of \(x\) affect the result?

Negative \(x\) subtracts from 10: \(x+10\). For \(x=-3\), \( -3+10=7\). The expression is valid for any real number \(x\).

Can I factor or expand \(x+10\)?

\(x+10\) is already simplified; it has no nontrivial factoring over the integers. You can factor a common factor if present, but here there is none besides 1.
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