Q. \(7 – 3 + 6 + x\)
Answer
Combine constants: \(7-3+6=10\), so the expression simplifies to \(10+x\).
Detailed Explanation
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Identify the terms.
The expression is \(7 – 3 + 6 + x\). The terms are the numbers 7, −3, 6 (constants) and the symbol \(x\) (a variable). You can only combine like terms: constants with constants, variables with the same variable.
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Separate constants from the variable.
Group the constants together and leave the variable term separate: \((7 – 3 + 6) + x\).
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Compute the constants step by step.
First compute \(7 – 3\):
\(7 – 3 = 4\).
Then add the remaining constant \(6\):
\(4 + 6 = 10\).
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Write the simplified expression.
Replace the constants by their sum and keep the variable term: \(10 + x\).
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Optional reorder (commutative property of addition).
You can also write the final result as \(x + 10\); both represent the same expression.
Final simplified form: \(10 + x\)
See full solution
FAQs
What is the simplified form of \(7-3+6+x\)?
Combine the numbers: \(7-3+6 = 10\). The simplified form is \(10+x\), which is usually written as \(x+10\).
What order of operations applies here?
Use left-to-right for addition and subtraction (same precedence). So do \(7-3=4\), then \(4+6=10\), then append \(+x\). No parentheses or exponents change the steps.
Can I rearrange the terms?
Yes. Addition is commutative, so \(7-3+6+x = x+10\). Treat subtraction as adding a negative: \(7+(-3)+6+x\), then reorder and combine.
How do I combine like terms?
Constants combine to one constant: \(7-3+6 = 10\). The variable term \(x\) is different, so the result is \(x+10\). Like terms share the same variable and exponent.
How do I evaluate the expression for a given \(x\)?
Substitute the value into \(x+10\). Example: if \(x=2\), then \(2+10=12\). If \(x=-5\), then \(-5+10=5\).
Can this expression be solved for \(x\)?
Can this expression be solved for \(x\)?
How do negative values of \(x\) affect the result?
Negative \(x\) subtracts from 10: \(x+10\). For \(x=-3\), \( -3+10=7\). The expression is valid for any real number \(x\).
Can I factor or expand \(x+10\)?
\(x+10\) is already simplified; it has no nontrivial factoring over the integers. You can factor a common factor if present, but here there is none besides 1.
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