Q. \[ \frac{d}{dx}\left(\sin^2(x)\right) \]
Answer
We use the chain rule. Let \(y=\sin^2(x)=[\sin(x)]^2\). Then
\[
\frac{dy}{dx}=2\sin(x)\cdot \cos(x)
\]
So the derivative of \(\sin^2(x)\) is
\[
2\sin(x)\cos(x)
\]
(Equivalently, it can be written as \(\sin(2x)\).)
Detailed Explanation
We want to find the derivative of the function \(y=\sin^2(x)\).
Step 1: Rewrite the function in a form that makes the chain rule clear.
The expression \(\sin^2(x)\) means \(\big(\sin(x)\big)^2\). So we can write:
\[
y=\big(\sin(x)\big)^2
\]
Step 2: Identify the outer and inner functions (Chain Rule).
Think of \(y\) as a composition:
-
Inner function: \(u=\sin(x)\)
-
Outer function: \(y=u^2\)
Step 3: Differentiate using the Chain Rule.
The Chain Rule says:
\[
\frac{dy}{dx}=\frac{dy}{du}\cdot\frac{du}{dx}
\]
Step 4: Compute each derivative separately.
First, differentiate the outer function \(y=u^2\) with respect to \(u\):
\[
\frac{dy}{du}=2u
\]
Next, differentiate the inner function \(u=\sin(x)\) with respect to \(x\):
\[
\frac{du}{dx}=\cos(x)
\]
Step 5: Substitute back \(u=\sin(x)\) and multiply.
Now combine them:
\[
\frac{dy}{dx}=2u\cdot \cos(x)
\]
Substitute \(u=\sin(x)\):
\[
\frac{dy}{dx}=2\sin(x)\cos(x)
\]
Final Answer.
\[
\frac{d}{dx}\left(\sin^2(x)\right)=2\sin(x)\cos(x)
\]
Graph
Calculus FAQ
What is the derivative of \( \sin^{2}(x) \)?
How do you differentiate \( \sin^{2}(x) \) using the product rule?
Can you simplify \(2\sin(x)\cos(x)\) into a single trig function?
What is the derivative of \( \sin^{2}(3x) \) ?
What is the derivative of \( (\sin x)^2 \) and are they the same as \( \sin^{2}(x) \)?
How do you differentiate \( \sin^{2}(x) \) if it’s written as \( \frac{1-\cos(2x)}{2} \)?
Check steps with three tools.
Math, Geometry, Trigonometry, etc.