Q. \[ \frac{d}{dx}\left(\sin^2(x)\right) \]

Answer

We use the chain rule. Let \(y=\sin^2(x)=[\sin(x)]^2\). Then

\[
\frac{dy}{dx}=2\sin(x)\cdot \cos(x)
\]

So the derivative of \(\sin^2(x)\) is

\[
2\sin(x)\cos(x)
\]

(Equivalently, it can be written as \(\sin(2x)\).)

Detailed Explanation

We want to find the derivative of the function \(y=\sin^2(x)\).

Step 1: Rewrite the function in a form that makes the chain rule clear.

The expression \(\sin^2(x)\) means \(\big(\sin(x)\big)^2\). So we can write:

\[
y=\big(\sin(x)\big)^2
\]

Step 2: Identify the outer and inner functions (Chain Rule).

Think of \(y\) as a composition:

  • Inner function: \(u=\sin(x)\)

  • Outer function: \(y=u^2\)

Step 3: Differentiate using the Chain Rule.

The Chain Rule says:

\[
\frac{dy}{dx}=\frac{dy}{du}\cdot\frac{du}{dx}
\]

Step 4: Compute each derivative separately.

First, differentiate the outer function \(y=u^2\) with respect to \(u\):

\[
\frac{dy}{du}=2u
\]

Next, differentiate the inner function \(u=\sin(x)\) with respect to \(x\):

\[
\frac{du}{dx}=\cos(x)
\]

Step 5: Substitute back \(u=\sin(x)\) and multiply.

Now combine them:

\[
\frac{dy}{dx}=2u\cdot \cos(x)
\]

Substitute \(u=\sin(x)\):

\[
\frac{dy}{dx}=2\sin(x)\cos(x)
\]

Final Answer.

\[
\frac{d}{dx}\left(\sin^2(x)\right)=2\sin(x)\cos(x)
\]

See full solution

Graph

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Calculus FAQ

What is the derivative of \( \sin^{2}(x) \)?

Use the chain rule: \(\frac{d}{dx}\sin^{2}(x)=2\sin(x)\cos(x)=\sin(2x)\).

How do you differentiate \( \sin^{2}(x) \) using the product rule?

Write \( \sin^{2}(x)=\sin(x)\sin(x)\). Then \(\frac{d}{dx}[\sin(x)\sin(x)]=\cos(x)\sin(x)+\sin(x)\cos(x)=2\sin(x)\cos(x)\).

Can you simplify \(2\sin(x)\cos(x)\) into a single trig function?

Yes. Use \(\sin(2x)=2\sin(x)\cos(x)\). So \(\frac{d}{dx}\sin^{2}(x)=\sin(2x)\).

What is the derivative of \( \sin^{2}(3x) \) ?

Chain rule with inner \(3x\): \(\frac{d}{dx}\sin^{2}(3x)=2\sin(3x)\cos(3x)\cdot 3=6\sin(3x)\cos(3x)=3\sin(6x)\).

What is the derivative of \( (\sin x)^2 \) and are they the same as \( \sin^{2}(x) \)?

They are the same. \(\frac{d}{dx}(\sin x)^2=2\sin(x)\cos(x)=\sin(2x)\).

How do you differentiate \( \sin^{2}(x) \) if it’s written as \( \frac{1-\cos(2x)}{2} \)?

Use identities: \(\sin^{2}(x)=\frac{1-\cos(2x)}{2}\). Then derivative is \(\frac{1}{2}(0-(-\sin(2x)\cdot 2))=\sin(2x)\).
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