Q. Determine the x-intercepts of the following equation. \( (2x+4)(4x-12)=y \)

Answer

Set y = 0: \(0=(2x+4)(4x-12)\).

Solve factors: \(2x+4=0\) so \(x=-2\). \(4x-12=0\) so \(x=3\).

x-intercepts: \((-2,0)\) and \((3,0)\).

Detailed Explanation

  1. Definition: An x-intercept is a point where the graph crosses the x-axis, so the y-coordinate is 0. Set y equal to 0 in the given equation.

    \[ (2x+4)(4x-12)=0 \]

  2. Apply the Zero-Product Property: If a product of two factors equals 0, then at least one of the factors must be 0. Set each factor equal to 0 separately.

    \[ 2x+4=0 \quad \text{or} \quad 4x-12=0 \]

  3. Solve the first equation 2x + 4 = 0.

    Subtract 4 from both sides:

    \[ 2x = -4 \]

    Divide both sides by 2:

    \[ x = -2 \]

  4. Solve the second equation 4x − 12 = 0.

    Add 12 to both sides:

    \[ 4x = 12 \]

    Divide both sides by 4:

    \[ x = 3 \]

  5. Conclusion: The x-intercepts are the points with these x-values and y = 0.

    \[ (-2,\,0) \quad \text{and} \quad (3,\,0) \]

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Algebra FAQs

What does x-intercept mean?

The x-intercepts are points where the graph crosses the x-axis, so \(y=0\). Solve the equation with \(y=0\) to find the x-values; each gives a point \((x,0)\).

How do I find the x-intercepts of \( (2x+4)(4x-12)=y \)?

Set \(y=0\): \((2x+4)(4x-12)=0\). Solve each factor: \(2x+4=0 \Rightarrow x=-2\); \(4x-12=0 \Rightarrow x=3\). X-intercepts: \((-2,0)\) and \((3,0)\).

Why is it valid to set each factor equal to zero?

If a product equals zero, at least one factor must be zero. So solving each linear factor yields all solutions for \(y = 0\). This follows from the zero-product property.

Should I simplify factors before solving?

You can, but it’s optional. For \(2x+4=0\) divide by \(2\) to get \(x=-2\). For \(4x-12=0\) divide by \(4\) to get \(x=3\). Simplifying makes arithmetic easier but doesn’t change solutions.

Do multiplicities matter for x-intercepts here?

Yes: a root’s multiplicity affects whether the graph crosses or just touches the axis. Both factors are linear (multiplicity 1), so the graph crosses the x-axis at \((-2,0)\) and \((3,0)\).

How do I check my answers?

How do I check my answers?

What is the \(y\)-intercept of this function?

Set \(x=0\): \(y=(2\cdot0+4)(4\cdot0-12)=4\cdot(-12)=-48\). Y-intercept is \((0,-48)\).

How would I graph this quickly?

Plot x-intercepts \((-2,0)\), \((3,0)\) and y-intercept \((0,-48)\); note the parabola opens upward (leading term \(8x^2\) positive). Sketch a smooth curve through these points..
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