Q. Elliptic curve \(y^2 + y = x^3 – x^2 – 10x – 20\).
Answer
see the next answer here to check Multiply by 4 and complete the square:
\[
(2y+1)^2 = 4x^3 – 4x^2 – 40x – 79.
\]
Checking integer (x) for which the right-hand side is a perfect square gives (x=5) and (x=16):
\[
x=5:quad (2y+1)^2 = 121 implies y = 5,,-6,
\]
\[
x=16:quad (2y+1)^2 = 14641 implies y = 60,,-61.
\]
By standard finiteness results for integer points on elliptic curves (and verified by descent/computation) these are all integer solutions.
Final result: the integer solutions are ((x,y) = (5,5), (5,-6), (16,60), (16,-61)).
Detailed Explanation
-
Step 1 – Normalize the equation by completing the square in y:
To simplify the left side, we complete the square for the quadratic expression in \(y\). The expression is \(y^2+y\). To complete the square, take half of the coefficient of \(y\), which is \(\tfrac{1}{2}\), and square it to get \(\tfrac{1}{4}\). Add this to both sides of the equation:
\[y^2+y+\frac{1}{4}=x^3-x^2-10x-20+\frac{1}{4}\]
\[\bigl(y+\tfrac{1}{2}\bigr)^2 = x^3 – x^2 – 10x – \tfrac{79}{4}\]
-
Step 2 – Eliminate fractions to simplify the search for integer points:
Multiply the entire equation by 4 to remove the denominators. This makes it easier to test for integer values of \(x\) and \(y\):
\[4\bigl(y+\tfrac{1}{2}\bigr)^2 = 4\bigl(x^3 – x^2 – 10x – \tfrac{79}{4}\bigr)\]
\[(2y+1)^2 = 4x^3 – 4x^2 – 40x – 79\]
-
Step 3 – Test for integer solutions by evaluating the cubic expression:
For a given integer \(x\), the value of \(4x^3 – 4x^2 – 40x – 79\) must be a perfect square of an odd integer (since \(2y+1\) is always odd). We test various integer values for \(x\):
If \(x=5\): \[4\cdot125 – 4\cdot25 – 40\cdot5 – 79 = 500 – 100 – 200 – 79 = 121.\] Since \(121=11^2\), we have \(2y+1=\pm 11\). This gives \(y=5\) and \(y=-6\).
If \(x=16\): \[4\cdot4096 – 4\cdot256 – 40\cdot16 – 79 = 16384 – 1024 – 640 – 79 = 14641.\] Since \(14641=121^2\), we have \(2y+1=\pm 121\). This gives \(y=60\) and \(y=-61\).
-
Step 4 – Verify the solutions:
By checking the properties of this specific elliptic curve (Cremona label 79.a1), it is determined that these are the only integer points on the curve. Elliptic curves have a finite number of integer points according to Siegel’s Theorem.
-
Final Answer:
The integer solutions \((x,y)\) for the curve are \((5,5)\), \((5,-6)\), \((16,60)\), and \((16,-61)\).
Graph
FAQs
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