Q. which graph represents the function \( f(x) = 2|x| \)?
Answer
The graph is a V-shaped graph with vertex at (0,0); for x≥0 the right arm is the line y=2x and for x<0 the left arm is the line y=−2x.
\(f(x)=2|x|=\begin{cases}2x,&x\ge0\\-2x,&x<0\end{cases}\)
Detailed Explanation
Which graph represents the function \( f(x) = 2|x| \)?
- Recall the definition of absolute value.The absolute value function is
\[
|x| = \begin{cases}
x & \text{if } x \ge 0,\\[6pt]
-x & \text{if } x < 0.
\end{cases}
\]This means for nonnegative x we keep x, and for negative x we take its negative so the result is nonnegative.
- Apply the factor 2 to the absolute value.Multiply the definition by 2 to get a piecewise formula for f:
\[
f(x) = 2|x| = \begin{cases}
2x & \text{if } x \ge 0,\\[6pt]
-2x & \text{if } x < 0.
\end{cases}
\]This gives two linear expressions, one for the right side (x ≥ 0) and one for the left side (x < 0).
- Find the vertex (the corner point).Evaluate at x = 0:
\[
f(0) = 2|0| = 0.
\]The graph has a corner (vertex) at the point (0, 0).
- Determine slopes of the two pieces.For x ≥ 0 the graph is the line y = 2x, which has slope 2.
For x < 0 the graph is the line y = −2x, which has slope −2.So the right arm rises to the right with slope 2 and the left arm rises to the left with slope 2 in absolute value (equivalently the left arm falls to the right with slope −2).
- Check symmetry, domain, and range.Symmetry: f is even because
\[
f(-x) = 2|-x| = 2|x| = f(x).
\]
The graph is symmetric about the y-axis.Domain: all real numbers, written as (−∞, ∞).
Range: f(x) ≥ 0 for all x, so the range is [0, ∞).
- Plot a few key points to see the shape.Compute f at simple x-values:
- f(0) = 0 → point (0, 0)
- f(1) = 2|1| = 2 → point (1, 2)
- f(2) = 4 → point (2, 4)
- f(−1) = 2 → point (−1, 2)
- f(−2) = 4 → point (−2, 4)
These points lie on two straight lines that meet at the origin.
- Describe the graph.The graph is a V-shaped curve with vertex at (0, 0). The right branch (x ≥ 0) is the line y = 2x. The left branch (x ≤ 0) is the line y = −2x. The V opens upward, is symmetric about the y-axis, and is steeper than y = |x| because of the vertical stretch factor 2.
- Final conclusion — which graph represents f(x) = 2|x|?The correct graph is the V-shaped graph with vertex at the origin, arms given by the lines y = 2x for x ≥ 0 and y = −2x for x ≤ 0, domain (−∞, ∞), and range [0, ∞). Equivalently, the graph obtained by taking y = |x| and stretching it vertically by a factor of 2.
Graph
Algebra FAQs
Which graph represents the function \(f(x)=2|x|\)?
How does \(f(x)=2|x|\) relate to \(y=|x|\)?
What are the equations of the two arms?.
What are the domain and range?
Where are the \(x\)- and \(y\)-intercepts?
Is the function even, odd, or neither?
On which intervals is the function increasing or decreasing?
How do I quickly sketch the graph?
How to check a point is on the graph?
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