Q. \((x-3)^2\)
Answer
Expand the square:
\[
(x-3)^2 = (x-3)(x-3)
\]
\[
= x^2 – 3x – 3x + 9 = x^2 – 6x + 9
\]
Final result:
\[
x^2 – 6x + 9
\]
Detailed Explanation
We are asked to expand the expression \( (x-3)^2 \). To do this step by step, we will use the algebra formula for squaring a binomial.
Step 1: Identify the binomial parts
The expression is \( (x-3)^2 \). This is a binomial of the form \( (a-b)^2 \), where:
- \(a = x\)
- \(b = 3\)
Step 2: Use the binomial square formula
The formula for squaring a binomial \( (a-b)^2 \) is:
\[
(a-b)^2 = a^2 – 2ab + b^2
\]
Step 3: Substitute \(a=x\) and \(b=3\)
Substitute into the formula:
\[
(x-3)^2 = x^2 – 2(x)(3) + 3^2
\]
Step 4: Simplify each term
Now simplify term by term.
Term 1:
\[
x^2
\]
Term 2:
Compute \( -2(x)(3) \):
\[
-2(x)(3) = -6x
\]
Term 3:
Compute \( 3^2 \):
\[
3^2 = 9
\]
Step 5: Combine the simplified terms
Put everything together:
\[
(x-3)^2 = x^2 – 6x + 9
\]
Final Answer
\[
(x-3)^2 = x^2 – 6x + 9
\]
Algebra FAQ
What does \((x-3)^2\) expand to?
How do you find the vertex of \(y=(x-3)^2\)?
What is the minimum value of \((x-3)^2\)?
Solve \((x-3)^2=0\).
Solve \((x-3)^2=9\).
What is the derivative of \((x-3)^2\)?
What is the domain and range of \((x-3)^2\)?
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