Q. \((x-3)^2\)

Answer

Expand the square:

\[
(x-3)^2 = (x-3)(x-3)
\]

\[
= x^2 – 3x – 3x + 9 = x^2 – 6x + 9
\]

Final result:

\[
x^2 – 6x + 9
\]

Detailed Explanation

We are asked to expand the expression \( (x-3)^2 \). To do this step by step, we will use the algebra formula for squaring a binomial.

Step 1: Identify the binomial parts

The expression is \( (x-3)^2 \). This is a binomial of the form \( (a-b)^2 \), where:

  • \(a = x\)
  • \(b = 3\)

Step 2: Use the binomial square formula

The formula for squaring a binomial \( (a-b)^2 \) is:

\[
(a-b)^2 = a^2 – 2ab + b^2
\]

Step 3: Substitute \(a=x\) and \(b=3\)

Substitute into the formula:

\[
(x-3)^2 = x^2 – 2(x)(3) + 3^2
\]

Step 4: Simplify each term

Now simplify term by term.

Term 1:

\[
x^2
\]

Term 2:

Compute \( -2(x)(3) \):

\[
-2(x)(3) = -6x
\]

Term 3:

Compute \( 3^2 \):

\[
3^2 = 9
\]

Step 5: Combine the simplified terms

Put everything together:

\[
(x-3)^2 = x^2 – 6x + 9
\]

Final Answer

\[
(x-3)^2 = x^2 – 6x + 9
\]

See full solution
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Algebra FAQ

What does \((x-3)^2\) expand to?

\((x-3)^2=x^2-6x+9\).

How do you find the vertex of \(y=(x-3)^2\)?

Vertex is at \((3,0)\) since \((x-h)^2\) has vertex \((h,0)\).

What is the minimum value of \((x-3)^2\)?

The minimum is \(0\), attained when \(x=3\).

Solve \((x-3)^2=0\).

\(x-3=0\), so \(x=3\).

Solve \((x-3)^2=9\).

\(x-3=\pm 3\), so \(x=6\) or \(x=0\).

What is the derivative of \((x-3)^2\)?

\(\frac{d}{dx}(x-3)^2=2(x-3)\).

What is the domain and range of \((x-3)^2\)?

Domain is all real numbers. Range is \(y\ge 0\).
Use AI to solve (x-3)² fast.
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