Q. \[ (x+4)(x-4) \]

Answer

Expand using the distributive property:

\[
(x+4)(x-4)=x(x-4)+4(x-4)=x^2-4x+4x-16=x^2-16.
\]

Final result:

\[
x^2-16.
\]

Detailed Explanation

We want to simplify the product \((x+4)(x-4)\).

Step 1: Recognize the structure

This expression matches the difference of squares pattern.

The difference of squares identity is:

\[
(a+b)(a-b)=a^2-b^2
\]

Step 2: Identify \(a\) and \(b\)

Compare \((x+4)(x-4)\) with \((a+b)(a-b)\).

We have:

\[
a=x,\quad b=4
\]

Step 3: Apply the identity

Substitute \(a=x\) and \(b=4\) into the formula \(a^2-b^2\):

\[
(x+4)(x-4)=x^2-4^2
\]

Step 4: Compute \(4^2\)

\[
4^2=16
\]

Step 5: Write the final simplified result

\[
(x+4)(x-4)=x^2-16
\]

See full solution

Graph

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Algebra FAQ

What is \( (x+4)(x-4) \) simplified?

\[\,(x+4)(x-4)=x^2-16.\]

Can this be recognized as a difference of squares?

Yes. Use \( (a+b)(a-b)=a^2-b^2 \) with \(a=x\), \(b=4\), giving \(x^2-16\).

What is the expanded form of \( (x+4)(x-4) \)?

Distribute: \(x(x-4)+4(x-4)=x^2-4x+4x-16=x^2-16\).

If \( (x+4)(x-4)=0 \), what are the solutions for \(x\)?

Set factors to zero: \(x+4=0\) so \(x=-4\), and \(x-4=0\) so \(x=4\).

What is the y-intercept when the expression is viewed as a function of \(x\)?

Evaluate at \(x=0\): \((0+4)(0-4)=4\cdot(-4)=-16\).

Is \( (x+4)(x-4) \) always nonnegative?

No. It equals \(x^2-16\), which is negative for \(-4<x<4\) and nonnegative for \(|x|\ge 4\).
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