Q. \(x^2 – 25\)

Answer

We solve the equation by factoring the difference of squares:

\[
x^2 – 25 = (x-5)(x+5) = 0
\]

So:

\[
x-5=0 \Rightarrow x=5,\quad x+5=0 \Rightarrow x=-5
\]

Final result: \(x=5\) or \(x=-5\).

Detailed Explanation

We want to simplify the expression \(x^2 – 25\).

Step 1: Recognize a difference of squares.

The expression \(x^2 – 25\) matches the pattern

\[
a^2 – b^2
\]

where \(a = x\) and \(b = 5\), because \(25 = 5^2\).

Step 2: Use the factoring formula.

The key identity is

\[
a^2 – b^2 = (a – b)(a + b)
\]

Substitute \(a = x\) and \(b = 5\).

Step 3: Factor the expression.

\[
x^2 – 25 = x^2 – 5^2 = (x – 5)(x + 5)
\]

This is the factored form.

Final Answer:

\[
x^2 – 25 = (x – 5)(x + 5)
\]

See full solution

Graph

image
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Algebra FAQ

What are the factors of \(x^2-25\)?

\(x^2-25=(x-5)(x+5)\).

Solve \(x^2-25=0\).

\(x^2=25\), so \(x=\pm 5\).

How do you use the difference of squares for \(x^2-25\)?

Recognize \(x^2-a^2\). Here \(a=5\), so \((x-5)(x+5)\).

What is the vertex form or completing-square form of \(x^2-25\)?

\(x^2-25\) is already a quadratic with completed square: \((x)^2-25\).

What is the graph intercepts of \(y=x^2-25\)?

\(y\)-intercept: \(x=0\Rightarrow y=-25\). \(x\)-intercepts: \(x=\pm 5\).

What is \(x^2-25\) in factored form if \(x=3\)?

Evaluate \(3^2-25=9-25=-16\). Factored check: \((3-5)(3+5)=(-2)(8)=-16\).
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