Q. \[ x^2+1 \]
Answer
We can factor the expression as a quadratic:
\[
x^2 + 1
\]
It does not factor over the real numbers into linear factors (since \(x^2=-1\) has no real solutions).
Final result: \(x^2 + 1\) (irreducible over the reals).
Detailed Explanation
Let’s solve the expression “\(x^2+1\)” by understanding what it means.
Step 1: Identify the expression.
The problem gives the expression:
\[
x^2+1
\]
Step 2: Note that no equation is provided.
You only wrote an expression, not an equation such as \(x^2+1=0\). Since there is no “equals” sign, there is nothing to solve for.
Step 3: Simplify if possible.
The expression \(x^2+1\) is already in simplest polynomial form. There are no like terms to combine and no multiplication to distribute.
Final Answer:
\[
x^2+1
\]
See full solution
Graph
Algebra FAQ
Factor and simplify \(x^2+1\).
\(x^2+1\) is irreducible over the reals and does not factor nicely with real numbers. Over complex numbers: \(x^2+1=(x-i)(x+i)\).
Find the roots of \(x^2+1=0\).
\(x^2=-1\). So \(x=\pm i\).
Solve \(x^2+1=5\).
\(x^2=4\), so \(x=\pm 2\).
Solve \(x^2+1\ge 0\).
\(x^2\ge -1\), which is true for all real \(x\). So the solution set is \(\mathbb{R}\).
Compute the derivative of \(x^2+1\).
\(\frac{d}{dx}(x^2+1)=2x\).
Find the integral \(\int (x^2+1)\,dx\).
\(\int x^2\,dx+\int 1\,dx=\frac{x^3}{3}+x+C\).
Determine the minimum value of \(x^2+1\) for real \(x\).
Since \(x^2\ge 0\), the minimum is \(1\), attained at \(x=0\).
Solve \(x^2+1\) step by step.
Use our AI tools for practice.
Use our AI tools for practice.
298,376+ active customers
Math, Geometry, Trigonometry, etc.
Math, Geometry, Trigonometry, etc.