Q. \(x^2+5x+4\)
Answer
\(x^2+5x+4\) factors as \((x+1)(x+4)\) since \(1\cdot 4=4\) and \(1+4=5\).
Final result: \((x+1)(x+4)\)
Detailed Explanation
We want to work with the polynomial \(x^2 + 5x + 4\). A common and useful step is to factor it, because factoring reveals the roots and helps with other algebra tasks.
Step 1: Identify the form to factor
The expression \(x^2 + 5x + 4\) is a quadratic of the form \(ax^2 + bx + c\), where:
\(a = 1\), \(b = 5\), and \(c = 4\).
Step 2: Factor using the “find two numbers” method
We look for two numbers \(m\) and \(n\) such that:
- \(m + n = 5\)
- \(mn = 4\)
Step 3: Choose the correct numbers
List the factor pairs of \(4\):
- \(1 \cdot 4 = 4\)
- \((-1) \cdot (-4) = 4\)
Now check sums:
- \(1 + 4 = 5\)
- \((-1) + (-4) = -5\)
The pair that gives the sum \(5\) is \(1\) and \(4\).
Step 4: Write the factored form
Substitute these values into the factor structure:
\[x^2 + 5x + 4 = (x + 1)(x + 4).\]
Final Answer
The expression factors as:
\[x^2 + 5x + 4 = (x + 1)(x + 4).\]
Graph
Algebra FAQ
Factorize \(x^2+5x+4\).
Solve \(x^2+5x+4=0\).
What are the \(x\)-intercepts of \(y=x^2+5x+4\)?
Complete the square for \(x^2+5x+4\).
Determine the vertex and minimum value of \(y=x^2+5x+4\).
Compute the discriminant of \(x^2+5x+4=0\).
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