Q. \(x^2+7x+12\)

Answer

Factor the quadratic \(x^2+7x+12\) by finding two numbers that multiply to \(12\) and add to \(7\). These numbers are \(3\) and \(4\).

\[
x^2+7x+12=(x+3)(x+4)
\]

Detailed Explanation

We want to simplify the expression

\(x^2 + 7x + 12\).

The expression is a quadratic, so we look for a way to factor it.

Step 1: Identify the form

A quadratic can often be written in factored form as

\((x+a)(x+b)\).

When we expand \((x+a)(x+b)\), we get

\((x+a)(x+b)=x^2+(a+b)x+ab\).

So we match coefficients with \(x^2 + 7x + 12\).

Step 2: Match the coefficients

We need:

\(a+b=7\)

and

\(ab=12\).

Step 3: Find numbers that satisfy both conditions

We need two numbers whose product is \(12\) and whose sum is \(7\).

The pair \(3\) and \(4\) works because:

\(3+4=7\)

and

\(3\cdot 4=12\).

Step 4: Write the factored form

Substitute \(a=3\) and \(b=4\) into \((x+a)(x+b)\):

\((x+3)(x+4)\).

Final Answer

\(x^2 + 7x + 12 = (x+3)(x+4)\).

See full solution

Graph

image
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Algebra FAQ

Factor \(x^2+7x+12\).

\(\left(x+3\right)\left(x+4\right)\).

Solve \(x^2+7x+12=0\).

\(\left(x+3\right)\left(x+4\right)=0\Rightarrow x=-3,\,-4\).

What are the roots of \(x^2+7x+12\)?

The roots are \(x=-3\) and \(x=-4\).

Find the discriminant of \(x^2+7x+12\).

\(a=1,b=7,c=12\). \(\Delta=b^2-4ac=49-48=1\).

Complete the square for \(x^2+7x+12\).

\(x^2+7x+12=\left(x+\frac{7}{2}\right)^2-\frac{1}{4}\).

Determine the vertex of \(y=x^2+7x+12\).

Vertex at \(x=-\frac{b}{2a}=-\frac{7}{2}\). Then \(y=\left(-\frac{7}{2}\right)^2+7\left(-\frac{7}{2}\right)+12=-\frac{1}{4}\).

Is \(x^2+7x+12\) always positive?

No. It factors to \(\left(x+3\right)\left(x+4\right)\), so it can be negative between \(-4\) and \(-3\).
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