Q. \(x^2+7x+12\)
Answer
Factor the quadratic \(x^2+7x+12\) by finding two numbers that multiply to \(12\) and add to \(7\). These numbers are \(3\) and \(4\).
\[
x^2+7x+12=(x+3)(x+4)
\]
Detailed Explanation
We want to simplify the expression
\(x^2 + 7x + 12\).
The expression is a quadratic, so we look for a way to factor it.
Step 1: Identify the form
A quadratic can often be written in factored form as
\((x+a)(x+b)\).
When we expand \((x+a)(x+b)\), we get
\((x+a)(x+b)=x^2+(a+b)x+ab\).
So we match coefficients with \(x^2 + 7x + 12\).
Step 2: Match the coefficients
We need:
\(a+b=7\)
and
\(ab=12\).
Step 3: Find numbers that satisfy both conditions
We need two numbers whose product is \(12\) and whose sum is \(7\).
The pair \(3\) and \(4\) works because:
\(3+4=7\)
and
\(3\cdot 4=12\).
Step 4: Write the factored form
Substitute \(a=3\) and \(b=4\) into \((x+a)(x+b)\):
\((x+3)(x+4)\).
Final Answer
\(x^2 + 7x + 12 = (x+3)(x+4)\).
Graph
Algebra FAQ
Factor \(x^2+7x+12\).
Solve \(x^2+7x+12=0\).
What are the roots of \(x^2+7x+12\)?
Find the discriminant of \(x^2+7x+12\).
Complete the square for \(x^2+7x+12\).
Determine the vertex of \(y=x^2+7x+12\).
Is \(x^2+7x+12\) always positive?
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