Q. Find the x-intercept of the line \(3x + 6y = 21\).

Answer

Set \(y=0\). Then \(3x=21\), so \(x=7\).

X-intercept: \((7,0)\)

Detailed Explanation

Solution — step-by-step

  1. Definition: The x-intercept is the point where the line crosses the x-axis, so the y-coordinate is 0. Therefore set y = 0.

  2. Substitute y = 0 into the equation 3x + 6y = 21:

    \[3x + 6(0) = 21\]

  3. Simplify the left side:

    \[3x + 0 = 21\]

    \[3x = 21\]

  4. Isolate x by dividing both sides by 3:

    \[x = \frac{21}{3}\]

    \[x = 7\]

  5. Thus the x-intercept is the point with coordinates

    \[(7,0)\]

  6. Check by substitution back into the original equation:

    \[3(7) + 6(0) = 21\]

    \[21 + 0 = 21\]

    Equality holds, so the result is correct.

See full solution

Graph

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FAQs

How do you find the x-intercept of a line?

Set y to 0 and solve. For example, for \(3x+6y=21\) set \(y=0\) giving \(3x=21\), so \(x=7\). The x-intercept is \((7,0)\).

What is the y-intercept of \(3x+6y=21\)?

Set \(x=0\): \(6y = 21\) so \(y = \frac{7}{2}\). The y-intercept is \(\left(0, \frac{7}{2}\right)\).

How do I get slope-intercept form from \(3x+6y=21\)?

Solve for \(y\): \(6y = 21 - 3x\) so \(y = -\frac{1}{2}x + \frac{7}{2}\). That is the slope-intercept form.

What is the slope of the line?

From \(y = -\frac{1}{2}x + \frac{7}{2}\) the slope is \(-\frac{1}{2}\).

How can I graph this line quickly?

Plot the intercepts \((7,0)\) and \((0, \frac{7}{2})\), then draw the straight line through them.

Can I write the equation in intercept form?

Can I write the equation in intercept form?

Are the intercepts integers?

The x-intercept 7 is an integer; the y-intercept \(\frac{7}{2}=3.5\) is not.

Does this line pass through the origin?

No. Plugging \((0,0)\) gives \(0\neq21\), so the origin is not on the line.
Find the x-intercept by setting y=0.
Solve for x.
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