Q. Find the y-intercept of the line \(18x – y = 5\).

Answer

Set x=0: \[18(0)-y=5,\ -y=5,\ y=-5.\]
Y-intercept: \[(0,-5)\]

Detailed Explanation

Find the y-intercept of the line 18x–y=5

  1. Recall the definition of the y-intercept.The y-intercept is the point at which the graph of the line crosses the y-axis. At any point on the y-axis the x-coordinate is 0, so to find the y-intercept we set x = 0 in the equation of the line.
  2. Substitute x = 0 into the equation.Start with the given equation:

    \(18x – y = 5\)

    Substitute \(x = 0\):

    \(18(0) – y = 5\).

  3. Simplify the left-hand side.Compute \(18(0)\):

    \(0 – y = 5\),
    which simplifies to

    \(-y = 5\).

  4. Solve for y.Multiply both sides of the equation \(-y = 5\) by \(-1\) to isolate y:

    \(y = -5\).

  5. State the y-intercept.The y-intercept point is \((0, -5)\). The y-intercept value (the y-coordinate where the line crosses the y-axis) is \(-5\).
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Algebra FAQs

How do I find the y-intercept from \(18x - y = 5\)?.

Set x=0 and solve: \(18(0)-y=5\) gives \(y=-5\). The y-intercept point is \((0,-5)\).

How do I rewrite the equation in slope-intercept form?

.

What is the slope of the line?

From \(y=18x-5\) the slope is \(m=18\).

What is the \(x\)-intercept of the line?.

Set \(y=0\): \(18x=5\) so \(x=\tfrac{5}{18}\). The x-intercept point is \(\left(\tfrac{5}{18},0\right)\).

How can I quickly graph this line?

Plot the y-intercept \(0,-5\) and another point like \(x=1\) gives \(y=13\), so plot \(1,13\). Draw the line through them (rise 18, run 1).

How do I find the y-intercept directly from \(Ax + By = C\)?

How do I find the y-intercept directly from \(Ax + By = C\)?

What does a negative \(y\)-intercept mean?

It means the line crosses the y-axis below the origin; here it crosses at \(y=-5\), so the point is \((0,-5)\).

How can I check my answer is correct?

Substitute \( (0,-5) \) into the original equation: \(18(0)-(-5)=5\) gives \(5=5\). The point satisfies the equation, so it's correct.
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