Q. Graph this function: \( y = x + 2 \). Click to select points on the graph.
Answer
\[ y = x + 2 \]
Slope = 1, y-intercept = 2. Easy points on the line: \((-2,0),\,(-1,1),\,(0,2),\,(1,3),\,(2,4)\).
Click any of those points.
Detailed Explanation
Graphing the function: \(y = x + 2\)
- Recognize the form and identify slope and intercept.The equation is in slope-intercept form \(y = mx + b\), so compare to get:
Slope: \(m = 1\).
y-intercept: \(b = 2\), which corresponds to the point \((0,2)\) where the line crosses the y-axis.
Interpretation of slope: a slope of \(1\) means that for each increase of 1 in x the value of y increases by 1 (rise of 1 for a run of 1).
- Choose convenient x-values and compute corresponding y-values.Pick easy x-values (for example: \(-2,-1,0,1,2\)) and use the rule \(y = x + 2\) to get y:
x Compute y = x + 2 Point (x,y) \(-2\) \(y = -2 + 2 = 0\) \((-2,\,0)\) \(-1\) \(y = -1 + 2 = 1\) \((-1,\,1)\) \(0\) \(y = 0 + 2 = 2\) \((0,\,2)\) \(1\) \(y = 1 + 2 = 3\) \((1,\,3)\) \(2\) \(y = 2 + 2 = 4\) \((2,\,4)\) - Plot the points on the coordinate plane.On your graph or graphing tool:
- Draw and label the x-axis and y-axis and choose an appropriate scale (one unit per tick mark is simplest).
- Mark and label each of the computed points: \((-2,0),\,(-1,1),\,(0,2),\,(1,3),\,(2,4).
- Any two distinct plotted points are sufficient to determine the line. For clarity plot at least three points to confirm they are collinear.
- Draw the line through the plotted points.Since this is a linear equation, all plotted points lie on one straight line. Use a ruler or the line tool in your graphing program to connect the points and extend the line across the graph in both directions. The line will pass through the y-intercept \((0,2)\) and rise one unit for every one unit moved to the right.
- Points to click (select) on the graph.Select any of these points to define or test the line. Recommended points to click:
- \((0,\,2)\)
- \((1,\,3)\)
- \((-2,\,0)\)
- \((2,\,4)\)
- \((-1,\,1)\)
Click any two of the above points to plot the line; clicking more points will verify correctness.
- Final description of the graph.The graph of \(y = x + 2\) is a straight line with slope \(1\) and y-intercept \(2\). Its points satisfy \(y – 2 = 1\cdot x\), so the line passes through the listed points and continues infinitely in both directions.
See full solution
Graph
Algebra FAQs
What is the slope and y-intercept of \( y = x + 2 \)?.
Slope \( m = 1 \). Y-intercept is \( (0,2) \) because when \( x = 0 \), \( y = 2 \).
Which two points should I click to draw the line?
Click two easy points: \( (0,2) \) and \( (-2,0) \). Alternatively use \( (0,2) \) and \( (1,3) \). Two points determine the line.
How do I find the x-intercept?
Set \( y=0 \): \( 0=x+2 \) so \( x=-2 \). X-intercept is \( (-2,0) \).
How can I test whether a point lies on the graph?
Substitute the point into \( y = x + 2 \). If equality holds, the point is on the line (e.g., test \( (3,5) \): \( 5 = 3+2 \) true).
What is the domain and range of \( y = x + 2 \)?
Domain: all real numbers. Range: all real numbers. A linear function with nonzero slope covers every real value.
How do I draw the line accurately by hand?.
How do I draw the line accurately by hand?.
How is this written in standard form?
Rearranged: \( x - y + 2 = 0 \) (or \( x - y = -2 \)) is standard form \( Ax+By+C=0 \).
Does the line rise or fall as \( x \) increases?.
It rises to the right because the slope \( m=1 \) is positive; for each increase of 1 in \( x \), \( y \) increases by 1.
How do I get more points quickly?
Pick any integer \( x \), compute \( y = x+2 \). Examples: \( x=-3 \rightarrow y=-1 \); \( x=4 \rightarrow y=6 \). Click those plotted points..
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