Q. Which graph represents \(y – 1 = 2(x – 2)\)?
Answer
Convert to slope-intercept form:
\[
y-1=2(x-2)\implies y-1=2x-4\implies y=2x-3.
\]
So the graph is a straight line with slope \(2\) and y-intercept \((0,-3)\). It passes through \((2,1)\) (and through \((1,-1)\), \((0,-3)\), etc.).
Final: the line \(y=2x-3\) (slope \(2\), y-intercept \(-3\)).
Detailed Explanation
-
Write the given equation:
\[ y – 1 = 2(x – 2) \] -
Expand the right-hand side:
\[ y – 1 = 2x – 4 \] -
Isolate \(y\) to get slope-intercept form:
Add 1 to both sides to obtain \( y = 2x – 3 \).
-
Identify slope and y-intercept:
The equation \( y = 2x – 3 \) has slope \( m = 2 \) and y-intercept \( b = -3 \) (point \( (0, -3) \)).
-
Find another point to plot:
Using the slope (rise/run = \( 2/1 \)) from \( (0, -3) \), move right 1 and up 2 to get point \( (1, -1) \). The given point-slope form also shows the line passes through \( (2, 1) \).
-
Locate the x-intercept (optional check):
Set \( y = 0 \): \( 0 = 2x – 3 \), so \( x = \frac{3}{2} = 1.5 \). The x-intercept is \( (1.5, 0) \).
-
Conclusion – which graph represents the line:
The correct graph is the straight line that crosses the y-axis at \( (0, -3) \) and rises with slope \( 2 \), passing through points such as \( (0, -3) \), \( (1, -1) \), and \( (2, 1) \). Any graph matching those features represents the equation \( y – 1 = 2(x – 2) \).
Graph
FAQs
Q What form is the equation in and what does it tell you?
Q How do I convert it to slope-intercept form?
Q What are the x- and y-intercepts?
Q How do I sketch the graph quickly?
Q How do I check if a given graph matches this line?
Q What does slope 2 mean in words?
Q What is the standard (general) form of the line?
Q Which lines are parallel or perpendicular to this one?
Q What are the domain and range of this line?
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