Q. Which graph represents \(y – 1 = 2(x – 4)\)?
Answer
Rewrite the equation: \(y-1=2(x-4)\) gives \(y-1=2x-8\), so \(y=2x-7\). This is the straight line with slope \(2\) and y-intercept \( (0,-7) \), passing through \( (4,1) \). Final: the graph is the line \(y=2x-7\).
Detailed Explanation
We are given the equation in point‑slope form. The goal is to identify the line it represents by converting to a more convenient form and extracting its key features.
Start from the equation in point‑slope form. Convert it to slope‑intercept form by expanding and isolating \(y\).
\[
y – 1 = 2(x – 4)
\]
Distribute on the right side.
\[
y – 1 = 2x – 8
\]
Add \(1\) to both sides to solve for \(y\).
\[
y = 2x – 8 + 1
\]
Combine like terms.
\[
y = 2x – 7
\]
From the slope‑intercept form \(y = 2x – 7\) we read off the slope and the y‑intercept. The slope is \(2\). The y‑intercept is \((0,-7)\).
We can also compute the x‑intercept by setting \(y = 0\) and solving for \(x\).
\[
0 = 2x – 7
\]
\[
2x = 7
\]
\[
x = \tfrac{7}{2} = 3.5
\]
So the line passes through the point \((4,1)\), has slope \(2\) (it rises 2 units for each 1 unit it runs to the right), crosses the y‑axis at \((0,-7)\), and crosses the x‑axis at \((3.5,0)\). Any graph that shows a straight line with these properties (slope \(2\), y‑intercept \(-7\), passing through \((4,1)\)) is the correct graph for the equation \(y – 1 = 2(x – 4)\).
Graph
Frequently Asked Questions
What is the slope of the line given by \(y-1=2(x-4)\)?
What is the y-intercept of the line?
What point is explicitly given by the point-slope form \(y-1=2(x-4)\)?
How do I graph the line quickly?
What is the x-intercept of the line?
ow do I write the equation in slope-intercept and standard form?
What is the equation of a line parallel or perpendicular to this one?
How can I test whether a point, for example \((3,-1)\), lies on the line?
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