Q. \[ \dfrac{9}{4}y – 12 = \dfrac{1}{4}y – 4 \]
Answer
Start with the equation.
\(\frac{9}{4}y-12=\frac{1}{4}y-4\)
Subtract \(\frac{1}{4}y\) from both sides.
\(\frac{9}{4}y-\frac{1}{4}y-12=-4\)
Simplify the \(y\)-terms.
\(\frac{8}{4}y-12=-4\)
\(2y-12=-4\)
Add \(12\) to both sides.
\(2y=8\)
Divide both sides by \(2\).
\(y=4\)
Final result: \(y=4\)
Detailed Explanation
Step-by-step solution
- Write the given equation.
\[ \tfrac{9}{4}y – 12 = \tfrac{1}{4}y – 4 \]
- To eliminate the fractions, multiply both sides of the equation by 4. Multiplying both sides by the same nonzero number preserves the equality.
\[ 4\bigg(\tfrac{9}{4}y – 12\bigg) = 4\bigg(\tfrac{1}{4}y – 4\bigg) \]
- Distribute 4 on each side and simplify the fractions:
\[ 9y – 48 = y – 16 \]
Explanation: 4 times 9/4 is 9, 4 times 12 is 48, 4 times 1/4 is 1, and 4 times 4 is 16.
- Collect the variable terms on one side by subtracting y from both sides (subtracting the same quantity from both sides preserves equality):
\[ 9y – 48 – y = y – 16 – y \]
Simplify:
\[ 8y – 48 = -16 \]
- Isolate the term with y by adding 48 to both sides (adding the same number to both sides preserves equality):
\[ 8y – 48 + 48 = -16 + 48 \]
Simplify:
\[ 8y = 32 \]
- Divide both sides by 8 to solve for y (dividing both sides by the same nonzero number preserves equality):
\[ y = \tfrac{32}{8} \]
Simplify:
\[ y = 4 \]
- Verify the solution by substituting y = 4 back into the original equation:
Left side: \[ \tfrac{9}{4}\cdot 4 – 12 = 9 – 12 = -3 \]
Right side: \[ \tfrac{1}{4}\cdot 4 – 4 = 1 – 4 = -3 \]
Both sides are equal, so y = 4 is correct.
Final answer: \[ y = 4 \]
Algebra FAQs
\(What is the solution to \(\dfrac{9}{4}y-12=\dfrac{1}{4}y-4\)?\)
How do I check that \( y = 4 \) is correct?
Why multiply both sides by \(4\)?
Can I solve without clearing denominators first?.
What common mistakes should I avoid?
What if the variable coefficients were equal on both sides?
How would I convert the equation to decimals?
How does this relate to graphing?
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