Q. \( \text{ag protons} \; \text{neutrons} \; \text{electrons} \).

Q: How do I find the number of protons (in an atom) from atomic number?

The atomic number Z equals the number of protons. So p = Z.

Q: How do I find the number of neutrons using mass number?

The mass number A is A = p + n. So neutrons n = A - Z.

Q: If an atom is neutral, how many electrons does it have?

For a neutral atom, electrons equal protons. So e = Z.

Q: How many electrons are there in an ion with charge q?

Use q. For charge q = +1, e = Z - 1. For q = -1, e = Z + 1. In general, e = Z - q.

Q: Given A = 35 and Z = 17, what are p, n, and e for the neutral atom?

p = 17, n = 35 - 17 = 18, and for neutral e = 17.

Q: If an ion is \text{Cl}^- with Z = 17, how do I get e?

Chloride has one extra electron. So e = Z + 1 = 17 + 1 = 18.

Q: What relationships connect A, Z, p, n, and e?

A = p + n, p = Z. For neutral atoms, e = Z. For ions, e = Z - q.

Answer

Interpret the question as asking for the basic numbers for an atom in terms of protons, neutrons, and electrons.

Let the atom have:

\(Z\) = number of protons, \(N\) = number of neutrons.

Then:

Protons: \(Z\)
Neutrons: \(N\)
Electrons (neutral atom): \(Z\)
Electrons (ion with charge \(q\)): \(Z – q\) (where \(q\) is positive for cations)

Final result: Protons \(= Z\), Neutrons \(= N\), Electrons \(= Z\) for a neutral atom (more generally \(Z-q\) for a charge \(q\)).

Detailed Explanation

To find the numbers of protons, neutrons, and electrons, you must know an isotope of silver (Ag), specifically the mass number \(A\) and the atomic number \(Z\) (and whether it’s neutral or an ion).

For silver, the atomic number is fixed:

\( Z = 47 \)

This means:

Step 1: Protons (for any neutral atom of Ag, and for any isotope of Ag)

\( \text{protons} = Z = 47 \)

Step 2: Neutrons

Use the isotope relation:

\[ A = Z + N \]

So the number of neutrons is:

\[ N = A – Z \]

Substitute \(Z = 47\):

\[ N = A – 47 \]

Step 3: Electrons

For a neutral silver atom:

\( \text{electrons} = Z = 47 \)

If the atom is an ion, you must be given the ionic charge. Then electrons change as follows:

\( \text{electrons} = Z – (\text{positive charge}) \)

or equivalently:

\( \text{electrons} = Z + (\text{magnitude of negative charge}) \)

What I need from you to finish with exact numbers:

1) Which isotope? (Example format: \(^{108}\text{Ag}\), or provide the mass number \(A\).)

2) Is it neutral, or what is the charge? (Example: \(\text{Ag}^+\), \(\text{Ag}^{2+}\), \(\text{Ag}^-\).)

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General Chemistry FAQs

How do I find the number of protons (in an atom) from atomic number?

The atomic number \(Z\) equals the number of protons. So \(p = Z\).

How do I find the number of neutrons using mass number?

The mass number \(A\) is \(A = p + n\). So neutrons \(n = A - Z\).

If an atom is neutral, how many electrons does it have?

For a neutral atom, electrons equal protons. So \(e = Z\).

How many electrons are there in an ion with charge \(q\)?

Use \(q\). For charge \(q = +1\), \(e = Z - 1\). For \(q = -1\), \(e = Z + 1\). In general, \(e = Z - q\).

Given \(A = 35\) and \(Z = 17\), what are \(p\), \(n\), and \(e\) for the neutral atom?

\(p = 17\), \(n = 35 - 17 = 18\), and for neutral \(e = 17\).

If an ion is \( \text{Cl}^- \) with \(Z = 17\), how do I get \(e\)?

Chloride has one extra electron. So \(e = Z + 1 = 17 + 1 = 18\).

What relationships connect \(A\), \(Z\), \(p\), \(n\), and \(e\)?

\(A = p + n\), \(p = Z\). For neutral atoms, \(e = Z\). For ions, \(e = Z - q\).

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