Q. br2 lewis dot structure.

Step-by-step solution: Bromine (Br) Lewis Dot Structure

Goal: Draw the Lewis dot structure for bromine, Br, showing its valence electrons as dots around the symbol.

Step 1: Determine the number of valence electrons.

Bromine is a halogen in Group 17 of the periodic table.

Group 17 elements have 7 valence electrons.

So, bromine has:

\[ \text{Valence electrons for Br} = 7 \]

Step 2: Write the element symbol.

Start with the symbol:

\[ \text{Br} \]

Step 3: Place 7 dots around the symbol.

Lewis dot structures represent valence electrons as individual dots.

For bromine, you place 7 dots around Br:

Place one dot on each side first, then add the remaining dots by pairing them.

A common arrangement is:

\[ \begin{matrix}
\text{(top)} & \cdot \\
\text{(left)} & \cdot \\
\text{(right)} & \cdot \\
\text{(bottom)} & \cdot \\
\end{matrix} \]

This uses 4 dots (one on each side). There are still 3 dots left, added as pairs:

Final Lewis dot structure (7 dots total):

\[ \text{Br} \; \cdot \;\; \cdot \\
\quad\quad \cdot \;\; \text{(center)} \;\; \cdot \\
\quad\quad \cdot \;\; \cdot \]

In words: bromine has 7 valence electrons, shown as 7 dots around Br.

Key result: Bromine’s Lewis dot structure is Br with 7 dots (one unpaired electron is present, characteristic of halogens).