Q. \(\frac{d}{dx}\sec^2(x)\)
Answer
To differentiate \( \sec^2(x) \), use the chain rule.
Let \(y=\sec(x)\). Then \( \sec^2(x)=\big(\sec(x)\big)^2\).
Differentiate: \(\frac{d}{dx}\big(\sec(x)\big)^2 = 2\sec(x)\cdot \frac{d}{dx}\sec(x)\).
And \(\frac{d}{dx}\sec(x)=\sec(x)\tan(x)\).
So the derivative is
\[
\frac{d}{dx}\sec^2(x)=2\sec(x)\cdot \sec(x)\tan(x)=2\sec^2(x)\tan(x).
\]
Detailed Explanation
We want to find the derivative of \( \sec^{2}(x) \). This means we are differentiating the function where the base is \( \sec(x) \) and the whole quantity is squared.
Step 1: Identify the outer and inner functions
Let \(u = \sec(x)\). Then the given function becomes
\[
\sec^{2}(x) = ( \sec(x) )^{2} = u^{2}.
\]
So we are differentiating \(u^{2}\) with respect to \(x\).
Step 2: Differentiate the outer function
Using the power rule, for \(u^{2}\) we have
\[
\frac{d}{dx}\left(u^{2}\right) = 2u \cdot \frac{du}{dx}.
\]
Step 3: Differentiate the inner function
Now we must compute \( \frac{du}{dx} \) where \(u = \sec(x)\).
Recall the derivative rule:
\[
\frac{d}{dx}\left(\sec(x)\right) = \sec(x)\tan(x).
\]
Therefore,
\[
\frac{du}{dx} = \sec(x)\tan(x).
\]
Step 4: Combine using the chain rule
Substitute \(u = \sec(x)\) and \( \frac{du}{dx} = \sec(x)\tan(x) \) into
\[
\frac{d}{dx}\left(u^{2}\right) = 2u \cdot \frac{du}{dx}.
\]
We get:
\[
\frac{d}{dx}\left(\sec^{2}(x)\right) = 2\sec(x)\left(\sec(x)\tan(x)\right).
\]
Step 5: Simplify
Multiply the factors \( \sec(x)\cdot \sec(x) \) to get \( \sec^{2}(x) \):
\[
2\sec(x)\left(\sec(x)\tan(x)\right) = 2\sec^{2}(x)\tan(x).
\]
Final Answer
\[
\frac{d}{dx}\left(\sec^{2}(x)\right) = 2\sec^{2}(x)\tan(x).
\]
Graph
Calculus FAQ
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