Q. \(\frac{d}{dx}\sec^2(x)\)

Answer

To differentiate \( \sec^2(x) \), use the chain rule.

Let \(y=\sec(x)\). Then \( \sec^2(x)=\big(\sec(x)\big)^2\).

Differentiate: \(\frac{d}{dx}\big(\sec(x)\big)^2 = 2\sec(x)\cdot \frac{d}{dx}\sec(x)\).

And \(\frac{d}{dx}\sec(x)=\sec(x)\tan(x)\).

So the derivative is

\[
\frac{d}{dx}\sec^2(x)=2\sec(x)\cdot \sec(x)\tan(x)=2\sec^2(x)\tan(x).
\]

Detailed Explanation

We want to find the derivative of \( \sec^{2}(x) \). This means we are differentiating the function where the base is \( \sec(x) \) and the whole quantity is squared.

Step 1: Identify the outer and inner functions

Let \(u = \sec(x)\). Then the given function becomes

\[
\sec^{2}(x) = ( \sec(x) )^{2} = u^{2}.
\]

So we are differentiating \(u^{2}\) with respect to \(x\).

Step 2: Differentiate the outer function

Using the power rule, for \(u^{2}\) we have

\[
\frac{d}{dx}\left(u^{2}\right) = 2u \cdot \frac{du}{dx}.
\]

Step 3: Differentiate the inner function

Now we must compute \( \frac{du}{dx} \) where \(u = \sec(x)\).

Recall the derivative rule:

\[
\frac{d}{dx}\left(\sec(x)\right) = \sec(x)\tan(x).
\]

Therefore,

\[
\frac{du}{dx} = \sec(x)\tan(x).
\]

Step 4: Combine using the chain rule

Substitute \(u = \sec(x)\) and \( \frac{du}{dx} = \sec(x)\tan(x) \) into

\[
\frac{d}{dx}\left(u^{2}\right) = 2u \cdot \frac{du}{dx}.
\]

We get:

\[
\frac{d}{dx}\left(\sec^{2}(x)\right) = 2\sec(x)\left(\sec(x)\tan(x)\right).
\]

Step 5: Simplify

Multiply the factors \( \sec(x)\cdot \sec(x) \) to get \( \sec^{2}(x) \):

\[
2\sec(x)\left(\sec(x)\tan(x)\right) = 2\sec^{2}(x)\tan(x).
\]

Final Answer

\[
\frac{d}{dx}\left(\sec^{2}(x)\right) = 2\sec^{2}(x)\tan(x).
\]

See full solution

Graph

image
Need help with derivatives? Try our AI homework tools now!
AI Homework Helper

Calculus FAQ

What is \(\\frac{d}{dx}\left(\sec(x)\right)\)?

\(\\frac{d}{dx}\left(\sec(x)\right)=\\sec(x)\\tan(x)\).

What is \(\\frac{d}{dx}\left(\sec^2(x)\right)\)?

Use chain rule. Let \(u=\\sec(x)\). Then \(\\frac{d}{dx}(u^2)=2u\\,u'\), so \(\\frac{d}{dx}(\\sec^2(x))=2\\sec(x)\\cdot(\\sec(x)\\tan(x))=2\\sec^2(x)\\tan(x)\).

How do you differentiate \(\\sec^2(x)\\tan(x)\)?

Product rule. \(\\frac{d}{dx}(\\sec^2 x\\tan x)=(2\\sec^2 x\\tan x)\\tan x+\\sec^2 x(\\sec^2 x)=2\\sec^2 x\\tan^2 x+\\sec^4 x\).

What is \(\\frac{d}{dx}\left(\\sec^2(3x)\right)\)?

Chain rule with inner \(3x\). \(\\frac{d}{dx}(\\sec^2(3x))=2\\sec(3x)\\tan(3x)\\cdot\\frac{d}{dx}(\\sec(3x))=2\\sec^2(3x)\\tan(3x)\\cdot 3=6\\sec^2(3x)\\tan(3x)\).

What is \(\frac{d}{dx}\left(\left(\sec(x)\right)^3\right)\)?

Use the power rule and the chain rule. \(\frac{d}{dx}\left(\sec^3 x\right)=3\sec^2 x\cdot\frac{d}{dx}\left(\sec x\right)\) The derivative of \(\sec x\) is \(\sec x\tan x\). \(\frac{d}{dx}\left(\sec^3 x\right)=3\sec^2 x\cdot\sec x\tan x\) Now multiply the powers of \(\sec x\). \(3\sec^2 x\cdot\sec x\tan x=3\sec^3 x\tan x\) Final answer: \(\frac{d}{dx}\left(\sec^3 x\right)=3\sec^3 x\tan x\)

Can you simplify \(2\\sec^2(x)\\tan(x)\) using identities?

Often no need. If desired, use \(\\tan^2 x=\\sec^2 x-1\) to rewrite when combined with \(\\tan^2 x\). For just \(2\\sec^2 x\\tan x\), it is already simplest.
Use the math helpers below to learn. Try, practice, and get help fast!
image
298,376+ active customers
Math, Geometry, Trigonometry, etc.
top
Upgrade to Edubrain Premium
Unlimited help across all subjects
$16
$3.99
/week
Core benefits:
  • ok Unlimited AI homework help
  • ok A+ quality answers
  • ok Faster responses, no limits
Tools:
  • ok Notes generator
  • ok Diagram generator
  • ok AI detector and humanizer
Extras:
  • ok Ad-free experience
  • ok Share responses with others
  • ok Advanced reasoning
expert
Expert-level help at discounted prices
Cancel anytime
Star
4.6Trusted by 14,623 students
🚀 Upgrade Plan
You’ve reached the free limit of 5 slides.
To generate a full presentation, please subscribe.
Unlock with subscription:
  • ok Unlimited slide generation for presentations
  • ok AI-designed, well-structured slide content
  • ok Faster workflow for bigger decks
-
Plus, get unlimited access to:
  • ok Diagram Generator, Flashcard Maker, Notes Generator, Research Assistant, Answer Generator, AI Homework Helper & AI Detector
  • ok Discounted designer expert help
Star
4.6Trusted by 14,623 students