Q. \(\dfrac{d}{dx}\left(n^{x}\right)\)
Answer
To differentiate \(n^x\) (with constant \(n>0\) and \(n\neq 1\)), rewrite using \(n^x=e^{x\ln n}\). Then use the chain rule.
\[
\frac{d}{dx}\left(n^x\right)=\frac{d}{dx}\left(e^{x\ln n}\right)=e^{x\ln n}\cdot \ln n=n^x\ln n
\]
Final answer: \(\frac{d}{dx}\left(n^x\right)=n^x\ln n\).
Detailed Explanation
We want to find the derivative of the function \(f(x)=n^x\), where \(n\) is a constant (with \(n>0\) and \(n\neq 1\)).
Step 1: Recall how to differentiate an exponential with base \(n\)
A standard result is: if \(f(x)=a^x\) where \(a>0\) and \(a\neq 1\), then
\[
\frac{d}{dx}\left(a^x\right)=a^x\ln(a).
\]
Here, the base is \(a=n\).
Step 2: Apply the formula with \(a=n\)
Substitute \(a=n\) into the derivative rule:
\[
\frac{d}{dx}\left(n^x\right)=n^x\ln(n).
\]
Final Answer
\[
\boxed{\frac{d}{dx}\left(n^x\right)=n^x\ln(n).}
\]
Calculus FAQ
What is the derivative of \(n^x\) (with constant \(n>0\), \(n\neq 1\))?
How do you derive \( \dfrac{d}{dx}\left(n^x\right)\) using \(a^x=e^{x\ln a}\)?
What if the base is \(e\)? What is \(\dfrac{d}{dx}(e^x)\)?
What is \(\dfrac{d}{dx}\left(5^{x}\right)\)?
What is the derivative of \(n^{u(x)}\) (chain rule)?
What is \(\dfrac{d}{dx}\left( (1/2)^{x}\right)\)?
Does the formula work for \(n\le 0\)?
Math, Geometry, Trigonometry, etc.