Q. Find the y-intercept of the line \(y=\frac{2}{5}x-\frac{14}{11}\).

Answer

Set x = 0: \(y = -\tfrac{14}{11}\). Thus the y-intercept is \(-\tfrac{14}{11}\).

Detailed Explanation

  1. Identify the form of the equation. The given line is
    \( y = \frac{2}{5}x – \frac{14}{11} \), which is in slope-intercept form \( y = mx + b \).
  2. Recall the definition of the y-intercept. In \( y = mx + b \), the y-intercept is the value of \( y \) when \( x = 0 \); it is the constant \( b \).
  3. Read off the constant term. Here the constant term is \( b = -\frac{14}{11} \).
  4. Verify by substituting \( x = 0 \):
    \[
    y = \frac{2}{5}\cdot 0 – \frac{14}{11} = 0 – \frac{14}{11} = -\frac{14}{11}.
    \]

Answer: -\(\dfrac{14}{11}\)

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Algebra FAQs

What is the y-intercept of \(y=\frac{2}{5}x-\frac{14}{11}\)?

Set \(x=0\): \(y=-\frac{14}{11}\). The \(y\)-intercept (as a number) is \(-\frac{14}{11}\)..

How do you find a y-intercept from slope-intercept form \(y=mx+b\)?.

In \(y=mx+b\) the \(y\)-intercept is \(b\). Plug \(x=0\) or read \(b\) directly; here \(m=\frac{2}{5}\) and \(b=-\frac{14}{11}\)..

What is the slope of the line \(y=\frac{2}{5}x-\frac{14}{11}\)?

The slope is \(m=\frac{2}{5}\)..

How do I write the \(y\)-intercept as an ordered pair?

The ordered-pair form is \( \left(0,-\frac{14}{11}\right) \)..

What is the y-intercept as a decimal?

-\( \frac{14}{11}=-1.\overline{27} \) (repeating).

How do I find the \(x\)-intercept of the same line?

How do I find the \(x\)-intercept of the same line?

Is \(-\frac{14}{11}\) fully simplified?

Yes. 14 and 11 have no common factors other than 1, so \(-\frac{14}{11}\) is in lowest terms.

If an equation is in standard form \(Ax + By = C\), how do I get the \(y\)-intercept?

Set \(x=0\) and solve for \(y\): \(y=\frac{C}{B}\). If \(B=0\) there is no finite \(y\)-intercept (vertical line).
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