Q. hcn formal charge.
Answer
In HCN, hydrogen (H) makes one bond to carbon, and nitrogen makes a triple bond to carbon. The structure is \( \mathrm{H{-}C{\equiv}N} \).
Formal charges (using \( \text{FC} = \text{valence} – (\text{nonbonding} + \frac{1}{2}\text{bonding}) \)):
\[
\text{FC(H)} = 1 – (0 + \tfrac{1}{2}\cdot 2) = 0
\]
\[
\text{FC(N)} = 5 – (4 + \tfrac{1}{2}\cdot 6) = 0
\]
\[
\text{FC(C)} = 4 – (0 + \tfrac{1}{2}\cdot 8) = 0
\]
So the formal charge on carbon is \(0\) (and all atoms have formal charge \(0\)).
Final result: \( \mathrm{HCN} \) has formal charge \(0\) on each atom, so carbon has formal charge \(0\).
Detailed Explanation
To find the formal charge in HCN, we first write the structure and then apply the formal charge formula to each atom.
Step 1: Write the usual Lewis structure of HCN
In HCN, hydrogen is single-bonded to carbon, and carbon is triple-bonded to nitrogen. A typical Lewis structure is:
\[
\text{H – C } \equiv \text{ N}
\]
This means:
- H forms one single bond to C
- C forms one single bond to H and three bonds to N (a total of 4 bonds around C)
- N forms a triple bond to C and has 1 lone pair
Step 2: Recall the formal charge formula
Use:
\[
\text{Formal charge} = V – (N_{\text{nonbonding}} + \tfrac{1}{2}N_{\text{bonding}})
\]
where:
- \(V\) is the number of valence electrons of the neutral free atom
- \(N_{\text{nonbonding}}\) is the number of electrons on the atom as lone pairs
- \(N_{\text{bonding}}\) is the total number of electrons shared in bonds involving that atom
Step 3: Formal charge on hydrogen (H)
Hydrogen has:
- Valence electrons \(V = 1\)
- No lone pairs, so \(N_{\text{nonbonding}} = 0\)
- One bond to carbon contributes \(N_{\text{bonding}} = 2\) electrons total around the H–C bond
So:
\[
\text{FC(H)} = 1 – \left(0 + \tfrac{1}{2}\cdot 2\right)
= 1 – 1
= 0
\]
Step 4: Formal charge on nitrogen (N)
Nitrogen has:
- Valence electrons \(V = 5\)
- One lone pair, so \(N_{\text{nonbonding}} = 2\)
- Triple bond to carbon means nitrogen is involved in three bonds. Total bonding electrons involving N is \(N_{\text{bonding}} = 6\)
So:
\[
\text{FC(N)} = 5 – \left(2 + \tfrac{1}{2}\cdot 6\right)
= 5 – \left(2 + 3\right)
= 0
\]
Step 5: Formal charge on carbon (C)
Carbon has:
- Valence electrons \(V = 4\)
- No lone pairs, so \(N_{\text{nonbonding}} = 0\)
- Carbon forms 4 bonds total (one to H and three to N), so its total bonding electrons are \(N_{\text{bonding}} = 8\)
So:
\[
\text{FC(C)} = 4 – \left(0 + \tfrac{1}{2}\cdot 8\right)
= 4 – 4
= 0
\]
Final answer: formal charges in HCN
- \(\text{FC(H)} = 0\)
- \(\text{FC(C)} = 0\)
- \(\text{FC(N)} = 0\)
Therefore, the molecule HCN has formal charge \(0\) on every atom.
General Chemistry FAQs
What is the formal charge on nitrogen in \( \mathrm{HCN} \)?
What is the formal charge on carbon in \( \mathrm{HCN} \)?
What is the formal charge on hydrogen in \( \mathrm{HCN} \)?
How do I compute formal charge for atoms in \( \mathrm{HCN} \)?
Which Lewis structure of \( \mathrm{HCN} \) gives the correct formal charges?
Is there an alternative resonance form of \( \mathrm{HCN} \) with nonzero formal charges?
Why does nitrogen carry no formal charge in \( \mathrm{HCN} \)?
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