Q. hcn formal charge.

Answer

In HCN, hydrogen (H) makes one bond to carbon, and nitrogen makes a triple bond to carbon. The structure is \( \mathrm{H{-}C{\equiv}N} \).

Formal charges (using \( \text{FC} = \text{valence} – (\text{nonbonding} + \frac{1}{2}\text{bonding}) \)):

\[
\text{FC(H)} = 1 – (0 + \tfrac{1}{2}\cdot 2) = 0
\]
\[
\text{FC(N)} = 5 – (4 + \tfrac{1}{2}\cdot 6) = 0
\]
\[
\text{FC(C)} = 4 – (0 + \tfrac{1}{2}\cdot 8) = 0
\]

So the formal charge on carbon is \(0\) (and all atoms have formal charge \(0\)).

Final result: \( \mathrm{HCN} \) has formal charge \(0\) on each atom, so carbon has formal charge \(0\).

Detailed Explanation

To find the formal charge in HCN, we first write the structure and then apply the formal charge formula to each atom.

Step 1: Write the usual Lewis structure of HCN

In HCN, hydrogen is single-bonded to carbon, and carbon is triple-bonded to nitrogen. A typical Lewis structure is:

\[
\text{H – C } \equiv \text{ N}
\]

This means:

  • H forms one single bond to C
  • C forms one single bond to H and three bonds to N (a total of 4 bonds around C)
  • N forms a triple bond to C and has 1 lone pair

Step 2: Recall the formal charge formula

Use:

\[
\text{Formal charge} = V – (N_{\text{nonbonding}} + \tfrac{1}{2}N_{\text{bonding}})
\]

where:

  • \(V\) is the number of valence electrons of the neutral free atom
  • \(N_{\text{nonbonding}}\) is the number of electrons on the atom as lone pairs
  • \(N_{\text{bonding}}\) is the total number of electrons shared in bonds involving that atom

Step 3: Formal charge on hydrogen (H)

Hydrogen has:

  • Valence electrons \(V = 1\)
  • No lone pairs, so \(N_{\text{nonbonding}} = 0\)
  • One bond to carbon contributes \(N_{\text{bonding}} = 2\) electrons total around the H–C bond

So:

\[
\text{FC(H)} = 1 – \left(0 + \tfrac{1}{2}\cdot 2\right)
= 1 – 1
= 0
\]

Step 4: Formal charge on nitrogen (N)

Nitrogen has:

  • Valence electrons \(V = 5\)
  • One lone pair, so \(N_{\text{nonbonding}} = 2\)
  • Triple bond to carbon means nitrogen is involved in three bonds. Total bonding electrons involving N is \(N_{\text{bonding}} = 6\)

So:

\[
\text{FC(N)} = 5 – \left(2 + \tfrac{1}{2}\cdot 6\right)
= 5 – \left(2 + 3\right)
= 0
\]

Step 5: Formal charge on carbon (C)

Carbon has:

  • Valence electrons \(V = 4\)
  • No lone pairs, so \(N_{\text{nonbonding}} = 0\)
  • Carbon forms 4 bonds total (one to H and three to N), so its total bonding electrons are \(N_{\text{bonding}} = 8\)

So:

\[
\text{FC(C)} = 4 – \left(0 + \tfrac{1}{2}\cdot 8\right)
= 4 – 4
= 0
\]

Final answer: formal charges in HCN

  • \(\text{FC(H)} = 0\)
  • \(\text{FC(C)} = 0\)
  • \(\text{FC(N)} = 0\)

Therefore, the molecule HCN has formal charge \(0\) on every atom.

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General Chemistry FAQs

What is the formal charge on nitrogen in \( \mathrm{HCN} \)?

For \( \mathrm{HCN} \), nitrogen typically has a formal charge of \(0\) when using the usual Lewis structure \( \mathrm{H{-}C\equiv N} \). Nitrogen’s valence electrons are fully accounted for by a triple bond and one lone pair.

What is the formal charge on carbon in \( \mathrm{HCN} \)?

Carbon has a formal charge of \(0\) in the standard structure \( \mathrm{H{-}C\equiv N} \). Carbon has no extra or missing electrons relative to its valence count under that bonding/lone-pair arrangement.

What is the formal charge on hydrogen in \( \mathrm{HCN} \)?

Hydrogen has a formal charge of \(0\). It has one bond to carbon and no lone pairs, matching its valence electron count.

How do I compute formal charge for atoms in \( \mathrm{HCN} \)?

Use \( \mathrm{FC = \#(valence) - \#(nonbonding) - \tfrac{1}{2}\#(bonding)} \). Then assign lone pairs to match a reasonable Lewis structure (for \( \mathrm{HCN} \), nitrogen has one lone pair).

Which Lewis structure of \( \mathrm{HCN} \) gives the correct formal charges?

The most common structure is \( \mathrm{H{-}C\equiv N} \) with one lone pair on nitrogen. This yields \( \mathrm{FC_N=0} \), \( \mathrm{FC_C=0} \), and \( \mathrm{FC_H=0} \).

Is there an alternative resonance form of \( \mathrm{HCN} \) with nonzero formal charges?

Some less common drawings can shift bonding (e.g., placing charge on carbon or nitrogen), but the dominant resonance form is the neutral \( \mathrm{H{-}C\equiv N} \) structure with all formal charges zero.

Why does nitrogen carry no formal charge in \( \mathrm{HCN} \)?

Nitrogen has valence \(5\). In \( \mathrm{H{-}C\equiv N} \), it has one lone pair (2 nonbonding electrons) and three bonds (6 bonding electrons). So \( \mathrm{FC_N = 5 - 2 - 3 = 0} \).
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