Q. How many electrons does Fe have?

Q: How many electrons does neutral iron (Fe) have?

Neutral Fe has atomic number Z=26, so it has 26 electrons.

Q: If Fe is ionized as \mathrm{Fe^{2+}} , how many electrons does it have?

\mathrm{Fe^{2+}} has lost 2 electrons, so 26-2=24 electrons.

Q: If Fe is ionized as \mathrm{Fe^{3+}} , how many electrons does it have?

\mathrm{Fe^{3+}} has lost 3 electrons, so 26-3=23 electrons.

Q: What is the electron configuration of neutral iron, and how many electrons does the configuration include?

Neutral Fe is 1s^2 2s^2 2p^6 3s^2 3p^6 3d^6 4s^2. Counting gives 2+2+6+2+6+6+2=26 electrons.

Q: How do you determine electrons for any metal ion of iron given its charge?

Use \text{electrons} = Z - (\text{positive charge}) . For Fe, Z=26. Example: \mathrm{Fe^{n+}} \Rightarrow 26-n electrons.

Q: What if iron forms \mathrm{Fe^-} ? How many electrons then?

\mathrm{Fe^-} has gained 1 electron, so 26+1=27 electrons.

Answer

Iron (Fe) is an element with atomic number 26. A neutral Fe atom has the same number of electrons as its atomic number.

Final result: \(26\) electrons.

Detailed Explanation

To determine how many electrons the element iron (Fe) has, you need its atomic number (the number of protons). For a neutral atom, the number of electrons equals the number of protons.

Step 1: Identify the atomic number of iron.

Iron (Fe) has atomic number：

\[ Z = 26 \]

Step 2: Use the relationship for a neutral atom.

For a neutral (uncharged) atom:

\[ \text{electrons} = \text{protons} = Z \]

Step 3: Substitute the atomic number.

\[ \text{electrons} = 26 \]

Conclusion:

Neutral iron (Fe) has \(\,26\,\) electrons.

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General Chemistry FAQs

How many electrons does neutral iron (Fe) have?

Neutral Fe has atomic number \(Z=26\), so it has \(26\) electrons.

If Fe is ionized as \( \mathrm{Fe^{2+}} \), how many electrons does it have?

\( \mathrm{Fe^{2+}} \) has lost 2 electrons, so \(26-2=24\) electrons.

If Fe is ionized as \( \mathrm{Fe^{3+}} \), how many electrons does it have?

\( \mathrm{Fe^{3+}} \) has lost 3 electrons, so \(26-3=23\) electrons.

What is the electron configuration of neutral iron, and how many electrons does the configuration include?

Neutral Fe is \(1s^2 2s^2 2p^6 3s^2 3p^6 3d^6 4s^2\). Counting gives \(2+2+6+2+6+6+2=26\) electrons.

How do you determine electrons for any metal ion of iron given its charge?

Use \( \text{electrons} = Z - (\text{positive charge}) \). For Fe, \(Z=26\). Example: \( \mathrm{Fe^{n+}} \Rightarrow 26-n\) electrons.

What if iron forms \( \mathrm{Fe^-} \)? How many electrons then?

\( \mathrm{Fe^-} \) has gained 1 electron, so \(26+1=27\) electrons.

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