Q. calculate boiling point
Answer
To compute a boiling point I need the substance, the external pressure or target pressure, and the enthalpy of vaporization. Use the Clausius-Clapeyron relation:
\[
\ln\frac{P_2}{P_1} = -\frac{\Delta H_{\text{vap}}}{R}\left(\frac{1}{T_2}-\frac{1}{T_1}\right).
\]
Solving for \(T_2\) gives
\[
\frac{1}{T_2} = \frac{1}{T_1} – \frac{R}{\Delta H_{\text{vap}}}\ln\frac{P_2}{P_1},
\quad
T_2 = \left(\frac{1}{T_1} – \frac{R}{\Delta H_{\text{vap}}}\ln\frac{P_2}{P_1}\right)^{-1}.
\]
Here \(R=8.314\ \mathrm{J\,mol^{-1}\,K^{-1}}\). Provide \(P_1, T_1, P_2,\) and \(\Delta H_{\text{vap}}\) and I will compute the numeric boiling point.
Detailed Explanation
Specify which of the following you mean, and give the numeric data required for that case. 1) A pure substance at a pressure other than 1 atm. 2) A solution (boiling point elevation) with given solute amount. 3) Boiling point at a given elevation above sea level. Provide the substance (for example water), the pressure \(P_2\) in pascals or atm if you mean case 1, or for a solution provide the solvent’s normal boiling point, the molality \(m\) and the van ‘t Hoff factor \(i\) if you mean case 2. If you want elevation, give the elevation in meters or the ambient pressure.
Method 1. Pure substance at a different pressure. Use the Clausius–Clapeyron relation. The equation is
\[
\ln\!\left(\frac{P_2}{P_1}\right) = -\frac{\Delta H_{\text{vap}}}{R}\left(\frac{1}{T_2}-\frac{1}{T_1}\right)
\]
Here \(P_1\) and \(T_1\) are a known reference pressure and temperature (for water, \(P_1=1\;\text{atm}\) and \(T_1=373.15\;\text{K}\) ), \(P_2\) is the new pressure, \(\Delta H_{\text{vap}}\) is the molar enthalpy of vaporization (J mol^{-1}), and \(R=8.314\;\text{J mol}^{-1}\text{K}^{-1}\). Solve for \(T_2\) by rearranging the equation to get
\[
\frac{1}{T_2} = \frac{1}{T_1} – \frac{R}{\Delta H_{\text{vap}}}\ln\!\left(\frac{P_2}{P_1}\right)
\]
Step-by-step instructions for Method 1. 1. Choose your reference state \(P_1,T_1\). 2. Look up or provide \(\Delta H_{\text{vap}}\) for the substance. 3. Insert \(P_2,P_1,\Delta H_{\text{vap}},R,T_1\) into the rearranged formula. 4. Compute the right-hand side to obtain \(1/T_2\). 5. Invert to get \(T_2\) in kelvin. 6. Convert to °C if desired by subtracting 273.15.
Method 2. Boiling point elevation for a solution. Use the colligative relation
\[
\Delta T_b = i\,K_b\,m
\]
where \(\Delta T_b\) is the increase in boiling temperature relative to the pure solvent’s normal boiling point, \(i\) is the van ‘t Hoff factor, \(K_b\) is the ebullioscopic constant of the solvent (°C kg mol^{-1}), and \(m\) is the molality (mol solute per kg solvent). The solution boiling point is
\[
T_{\text{solution}} = T_{\text{pure solvent}} + \Delta T_b
\]
Step-by-step instructions for Method 2. 1. Provide the pure solvent boiling point \(T_{\text{pure solvent}}\). 2. Provide the molality \(m\) of the solute and the van ‘t Hoff factor \(i\). 3. Look up or provide \(K_b\) for the solvent. 4. Compute \(\Delta T_b = i K_b m\). 5. Add \(\Delta T_b\) to the pure solvent boiling point to get the solution boiling point.
Other practical notes. For elevation you can convert elevation to approximate ambient pressure and then use Method 1. For modest pressure changes you may use tabulated vapor pressure data or Antoine equation parameters if available. If you supply the substance and numeric data now, I will compute the boiling point step-by-step with numbers and show every arithmetic step.
Chemistry FAQs
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