Q. how to calculate the average atomic mass

Answer

Average atomic mass is the weighted mean of isotope masses using their fractional abundances. Convert percent abundances to fractions, multiply each isotope mass by its fraction, and sum. The formula is
\[ \overline{M} = \sum_i f_i m_i \]
where \(f_i\) are fractional abundances and \(\sum_i f_i = 1\). For example, isotopes 10 u at 25% and 11 u at 75% give \(0.25 \times 10 + 0.75 \times 11 = 10.75\) u.

Detailed Explanation

The average atomic mass of an element is the weighted mean of the masses of its naturally occurring isotopes, with weights given by the isotopic abundances. This tells you the average mass of an atom of that element as it occurs in nature. In symbols, the average atomic mass is the sum over all isotopes of the product of each isotope’s fractional abundance and its isotopic mass.

Write the general formula. Use fractional abundances \(p_i\) for isotope \(i\) and isotopic masses \(m_i\). The fractional abundances satisfy \(\sum_{i=1}^n p_i = 1\). The average atomic mass \(\bar{m}\) is

\[
\bar{m} \;=\; \sum_{i=1}^n p_i \, m_i
\]

Step 1 Convert percentage abundances to decimals. If an isotope has abundance given as a percent, for example 98.93 percent, convert it to fractional abundance by dividing by 100, giving 0.9893. Always check that the fractional abundances sum to 1 within rounding error.

Step 2 Multiply each isotopic mass by its fractional abundance. For each isotope compute the product \(p_i \, m_i\). These products are the contributions of each isotope to the average mass.

Step 3 Add the contributions. Sum the products from Step 2 to obtain the average atomic mass. Use appropriate significant figures and units of atomic mass unit, denoted \mathrm{u}.

Step 4 Example calculation. For carbon, two common isotopes are carbon-12 with isotopic mass \(12.000000 \, \mathrm{u}\) and natural abundance 98.93 percent, and carbon-13 with isotopic mass \(13.003355 \, \mathrm{u}\) and natural abundance 1.07 percent. Convert abundances to fractions 0.9893 and 0.0107 respectively, then apply the formula.

\[
\bar{m}_{\mathrm{C}} \;=\; (0.9893) \times 12.000000 \;+\; (0.0107) \times 13.003355
\]

Compute each product explicitly.

\[
(0.9893) \times 12.000000 \;=\; 11.871600
\]

\[
(0.0107) \times 13.003355 \;=\; 0.1391358985
\]

Sum the contributions to get the average atomic mass.

\[
\bar{m}_{\mathrm{C}} \;=\; 11.871600 \;+\; 0.1391358985 \;=\; 12.0107358985 \, \mathrm{u}
\]

Step 5 Round to appropriate significant figures. Atomic weights are typically reported to three decimal places for common elements, so round to 12.011 \, \mathrm{u}. That gives the standard value reported in tables.

Summary of procedure:

1. Convert percent abundances to fractional abundances by dividing by 100. 2. Multiply each fractional abundance by the corresponding isotopic mass. 3. Sum these products. 4. Round the result appropriately. The final number is the average atomic mass of the element.

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Chemistry FAQs

What is average atomic mass?

The weighted mean mass of an element's isotopes. Formula: \[ \bar{M} = \sum_i f_i m_i \] where \(f_i\) are fractional abundances that sum to 1, and \(m_i\) are isotope masses in atomic mass units, u (amu).

How do I convert percent abundance to fraction?

Divide by 100. For 20% use \(f=20\%/100=0.20\). Use fractional abundances so that \(\sum_i f_i = 1\) before applying the weighted average.

How do I calculate average atomic mass step by step?

Convert percents to fractions, multiply each fraction by its isotope mass, then sum. Example: \(\bar{M}=0.6915(63.93)+0.3085(65.93)\). Compute the products, then add the results.

What units are used for average atomic mass?

Use atomic mass units, written u or amu. Numerically equal to grams per mole when reporting molar mass. Also \(1\ \text{u}=\frac{1\ \text{g}}{N_A}\), where \(N_A\) is Avogadro's number.

How do I find percent abundance if I only know the average and isotope masses?

For two isotopes, let \(x\) be fraction of isotope 1. Solve \(x m_1 + (1-x) m_2 = \bar{M}\). Then \(x = \frac{\bar{M}-m_2}{m_1-m_2}\). Multiply by 100 to get percent. For more isotopes, solve linear system.

What if given abundances do not sum to 100%?

Normalize them. Compute total \(T=\sum_i p_i\). Convert each to fraction \(f_i=(p_i/T)\). Then use \(\bar{M}=\sum_i f_i m_i\). This corrects measurement or rounding errors.

How do I include measurement uncertainties in the average mass?

Propagate errors with weighted variance. For independent isotope mass uncertainties \( \sigma_i\), the uncertainty in \(\bar{M}\) is \(\sigma_{\bar{M}}=\sqrt{\sum_i f_i^2 \sigma_i^2}\). Include abundance uncertainties using full error propagation if needed.
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