Q. \( \)molar mass of \( \mathrm{C_2H_6} \).

Q: Molar mass of \mathrm{C_2H_6} ?

\mathrm{C_2H_6} : 2(12.01) + 6(1.008) = 24.02 + 6.048 = 30.07\ \mathrm{g/mol} (approx. 30.08\ \mathrm{g/mol} using 1.00 and 12.01).

Q: What atomic masses should I plug into 2\times \mathrm{C} + 6\times \mathrm{H} ?

Use \mathrm{C} \approx 12.01\ \mathrm{g/mol} and \mathrm{H} \approx 1.008\ \mathrm{g/mol}. Then multiply by subscripts 2 and 6.

Q: How do subscripts affect molar mass in \mathrm{C_2H_6} ?

Subscripts give the number of atoms. For \mathrm{C_2H_6} , there are 2 carbons and 6 hydrogens, so the molar mass is 2M(\mathrm{C}) + 6M(\mathrm{H}).

Q: Can I use \mathrm{M}(\mathrm{H}) = 1.00\ \mathrm{g/mol} and \mathrm{M}(\mathrm{C}) = 12.00\ \mathrm{g/mol} ?

Yes for quick estimates: 2(12.00) + 6(1.00) = 24.00 + 6.00 = 30.00\ \mathrm{g/mol}. More precise tables give about 30.07\ \mathrm{g/mol}.

Q: What’s the molar mass of \mathrm{C_2H_6} in kilograms per mole ?

30.07\ \mathrm{g/mol} = 0.03007\ \mathrm{kg/mol}.

Q: How do I round the final answer for molar mass?

Round based on given atomic masses. If using 12.01 and 1.008, report 30.07\ \mathrm{g/mol} (often 30.1\ \mathrm{g/mol} to 3 sig figs).

Answer

To find the molar mass of \( \mathrm{C_2H_6} \), add the atomic masses of each atom.

\( \mathrm{C}:\ 2 \times 12.01 = 24.02\)

\(\mathrm{H}:\ 6 \times 1.008 = 6.048\)

\[
\text{Molar mass of } \mathrm{C_2H_6} = 24.02 + 6.048 = 30.068\ \text{g/mol}
\]

Final answer: \(30.07\ \text{g/mol}\)

Detailed Explanation

To find the molar mass of the compound \( \mathrm{C_2H_6} \), you add the atomic masses of all atoms in one formula unit.

Step 1: Identify how many atoms of each element are present

\(\mathrm{C_2H_6}\) contains:

\(2\) atoms of carbon (C)
\(6\) atoms of hydrogen (H)

Step 2: Write the molar mass calculation setup

Use standard atomic masses:

Carbon: \(12.01\ \mathrm{g/mol}\)
Hydrogen: \(1.008\ \mathrm{g/mol}\)

Now multiply each by the number of atoms and add:

\[
\text{Molar mass of } \mathrm{C_2H_6}
= 2(12.01) + 6(1.008)
\]

Step 3: Calculate each part

Carbon contribution:

\[
2(12.01) = 24.02
\]

Hydrogen contribution:

\[
6(1.008) = 6.048
\]

Step 4: Add the results

\[
24.02 + 6.048 = 30.068
\]

Step 5: Final answer (with appropriate rounding)

\[
\text{Molar mass of } \mathrm{C_2H_6} \approx 30.07\ \mathrm{g/mol}
\]

See full solution

Need help with chemistry? Try our AI homework tools!

AI helper

General Chemistry FAQs

Molar mass of \( \mathrm{C_2H_6} \) ?

\( \mathrm{C_2H_6} \): \(2(12.01) + 6(1.008) = 24.02 + 6.048 = 30.07\ \mathrm{g/mol}\) (approx. \(30.08\ \mathrm{g/mol}\) using \(1.00\) and \(12.01\)).

What atomic masses should I plug into \(2\times \mathrm{C} + 6\times \mathrm{H}\) ?

Use \( \mathrm{C} \approx 12.01\ \mathrm{g/mol}\) and \( \mathrm{H} \approx 1.008\ \mathrm{g/mol}\). Then multiply by subscripts \(2\) and \(6\).

How do subscripts affect molar mass in \( \mathrm{C_2H_6} \) ?

Subscripts give the number of atoms. For \( \mathrm{C_2H_6} \), there are \(2\) carbons and \(6\) hydrogens, so the molar mass is \(2M(\mathrm{C}) + 6M(\mathrm{H})\).

Can I use \( \mathrm{M}(\mathrm{H}) = 1.00\ \mathrm{g/mol}\) and \( \mathrm{M}(\mathrm{C}) = 12.00\ \mathrm{g/mol}\) ?

Yes for quick estimates: \(2(12.00) + 6(1.00) = 24.00 + 6.00 = 30.00\ \mathrm{g/mol}\). More precise tables give about \(30.07\ \mathrm{g/mol}\).

What’s the molar mass of \( \mathrm{C_2H_6} \) in kilograms per mole ?

\(30.07\ \mathrm{g/mol} = 0.03007\ \mathrm{kg/mol}\).

How do I round the final answer for molar mass?

Round based on given atomic masses. If using \(12.01\) and \(1.008\), report \(30.07\ \mathrm{g/mol}\) (often \(30.1\ \mathrm{g/mol}\) to 3 sig figs).

Find molar mass of C2H6.
Use math helpers to check.

301,983+ active customers
Analytical, General, Biochemistry, etc.

Chemistry AI Science AI Solver AI homework helper