Q. molar mass of \( \mathrm{HNO_3} \).
Answer
Molar mass of nitric acid, \( \text{HNO}_3 \).
Count atoms: \(1\) H, \(1\) N, \(3\) O.
Using atomic masses: \( \text{H} = 1.01\), \( \text{N} = 14.01\), \( \text{O} = 16.00\).
\[
\text{Molar mass} = 1(1.01) + 1(14.01) + 3(16.00) = 63.02\ \text{g/mol}
\]
Final result: \(63.02\ \text{g/mol}\).
Detailed Explanation
To find the molar mass of \( \mathrm{HNO_3} \), add the atomic masses of all atoms in one molecule.
Step 1: Identify the elements and their counts
\( \mathrm{HNO_3} \) contains:
- \(1\) atom of hydrogen, \( \mathrm{H} \)
- \(1\) atom of nitrogen, \( \mathrm{N} \)
- \(3\) atoms of oxygen, \( \mathrm{O} \)
Step 2: Write the molar mass sum
Using atomic masses (in \( \mathrm{g/mol} \)):
- \( \mathrm{H} \approx 1.01\)
- \( \mathrm{N} \approx 14.01\)
- \( \mathrm{O} \approx 16.00\)
Now add them according to the subscripts in \( \mathrm{HNO_3} \):
\[
M(\mathrm{HNO_3}) = 1(1.01) + 1(14.01) + 3(16.00)
\]
Step 3: Calculate each part
\[
1(1.01) = 1.01
\]
\[
1(14.01) = 14.01
\]
\[
3(16.00) = 48.00
\]
Step 4: Add everything
\[
M(\mathrm{HNO_3}) = 1.01 + 14.01 + 48.00 = 63.02
\]
Final Answer
The molar mass of \( \mathrm{HNO_3} \) is \( \boxed{63.02\ \mathrm{g/mol}} \).
General Chemistry FAQs
How do I calculate the molar mass of \(\mathrm{HNO_3}\)?
What is the molar mass of \(\mathrm{HNO_3}\) using common atomic weights?
What are the molar masses of each element in \(\mathrm{HNO_3}\)?
Why does \(\mathrm{O}\) contribute \(3 \times 16\) to the molar mass of \(\mathrm{HNO_3}\)?
How many grams of \(\mathrm{HNO_3}\) are in 1 mole?
What is the molar mass of \(\mathrm{HNO_3}\) in kilograms per mole?
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