Q. \(n_2\) lewis dot diagram.

Answer

\(<\)Lewis dot diagram for \( \mathrm{N_2}\) (nitrogen molecule\(>\)):

\( \mathrm{N_2}\) has \(2 \times 5 = 10\) valence electrons total. The stable structure is a triple bond between the two nitrogens, with one lone pair on each nitrogen.

Bonding: \( \mathrm{N \equiv N}\)

Lone pairs: 1 lone pair on the left N and 1 lone pair on the right N.

\[
\begin{array}{c}
\mathrm{:N:\ \equiv\ \ :N:}
\end{array}
\]

Electron count check: Triple bond uses \(6\) electrons, and two lone pairs use \(4\) electrons; total \(6 + 4 = 10\).

Detailed Explanation

In chemistry, “N” is nitrogen (nitrogen commonly has valence electrons of 5). But “n2” could also mean “\( \text{N}_2 \)” (nitrogen gas).

Below I will give the Lewis dot diagram for nitrogen gas, \( \text{N}_2 \), because “\( \text{n2} \)” most naturally refers to \( \text{N}_2 \).

Step 1: Determine the number of valence electrons

Nitrogen is in Group 15 of the periodic table.

That means each nitrogen atom has \(5\) valence electrons.

\( \text{N}_2 \) contains two nitrogen atoms, so the total valence electrons are:

\[ 2 \times 5 = 10 \]

Step 2: Decide the bonding type

Each nitrogen wants to reach the noble-gas configuration (an octet) around it.

Nitrogen typically forms a triple bond to satisfy this efficiently.

So the bonding is a triple bond between the two nitrogen atoms:

\[ :\text{N}\equiv\text{N}: \]

(The colons represent nonbonding electron pairs that will be added next.)

Step 3: Count electrons around each nitrogen

A triple bond consists of \(3\) shared pairs, which is \(6\) electrons total.

Each nitrogen then has \(3\) shared pairs, and we must add lone pairs so that each nitrogen has \(8\) electrons around it.

For a nitrogen triple bond, each nitrogen ends up with one lone pair.

Step 4: Draw the complete Lewis dot diagram

Each nitrogen shows:

  • \(3\) bonding pairs in the triple bond
  • \(1\) lone pair

Complete Lewis dot diagram (with lone pairs shown as pairs of dots on each nitrogen):

\[ \text{N}:\ \equiv\ \text{N}: \]

More explicitly, you can think of it as:

\[
\begin{matrix}
\cdot & & & \cdot \\
\cdot & \text{N} & \equiv & \text{N} \\
\cdot & & & \cdot
\end{matrix}
\]

In that form, the extra dots on each side represent the one lone pair on each nitrogen.

Final answer

The Lewis dot diagram for \( \text{N}_2 \) is a triple bond with one lone pair on each nitrogen:

\[ \text{N}:\ \equiv\ \text{N}: \]

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General Chemistry FAQs

How many valence electrons does \(N_2\) have for building a Lewis dot diagram?

Nitrogen has \(5\) valence electrons. For \(N_2\), total valence electrons \(=2 \times 5=10\).

What is the Lewis structure (bond type) for \(N_2\)?

\(N_2\) has a triple bond: \(\text{\(N \equiv N\)}\). Each nitrogen has a complete octet.

How many lone pairs are on each nitrogen in the \(N_2\) Lewis dot diagram?

Each nitrogen has \(1\) lone pair. The remaining electrons form the triple bond.

How do you place electrons to make octets for \(N_2\)?

Start with \(10\) valence electrons. Form a triple bond (uses \(6\) electrons). The remaining \(4\) electrons make \(1\) lone pair on each N.

What is the formal charge on nitrogen in the correct Lewis structure of \(N_2\)?

Formal charge on each N is \(0\). Triple bond plus one lone pair satisfies the valence accounting.

What electron geometry and bond order correspond to the Lewis structure of \(N_2\)?

Bond order is \(3\) from \(N \equiv N\). With two bonded atoms, geometry is linear (\(180^\circ\)).
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