Q. negative plus a positive equals
Answer
Let \(x>0\) and \(y>0\). Consider \( -x + y \).
– If \(y > x\): \( -x + y = y – x > 0\) (positive).
– If \(y = x\): \( -x + y = 0\).
– If \(y < x\): \( -x + y = -(x - y) < 0\) (negative).
Detailed Explanation
Problem: “negative plus a positive” — step-by-step explanation
We will explain, in full detail, how to evaluate a sum in which one addend is negative and the other is positive. Write the negative number as \(-a\) with \(a>0\), and the positive number as \(b\) with \(b>0\).
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Rewrite the sum in a subtraction form.
The expression \(-a + b\) can be rewritten by moving terms so that the positive quantity comes first:
\[ -a + b = b – a. \]
Explanation: adding a negative number is the same as subtracting its absolute value. So \(-a + b\) is the same operation as subtracting \(a\) from \(b\).
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Compare the absolute values.
To determine the sign of the result, compare \(a\) and \(b\):
- If \(b > a\), the positive number has the larger absolute value, so the result is positive.
- If \(b < a\), the negative number (in absolute value \(a\)) is larger, so the result is negative.
- If \(b = a\), the numbers cancel and the result is zero.
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Compute the numerical result by subtracting the smaller absolute value from the larger, and attach the sign of the larger.
Using the comparison above, compute the difference and determine the sign:
- Case \(b > a\): \[ -a + b = b – a \quad\text{(positive result)}. \]
- Case \(b < a\): \[ -a + b = -(a - b) \quad\text{(negative result)}. \]
- Case \(b = a\): \[ -a + b = 0. \]
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Worked examples (each shown step-by-step).
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Example 1: Evaluate \(-3 + 5\).
Step 1: Rewrite as subtraction: \[ -3 + 5 = 5 – 3. \]
Step 2: Compare absolute values: \(5 > 3\), so result is positive.
Step 3: Subtract: \[ 5 – 3 = 2. \]
Answer: \[ -3 + 5 = 2. \]
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Example 2: Evaluate \(-7 + 4\).
Step 1: Rewrite: \[ -7 + 4 = 4 – 7. \]
Step 2: Compare absolute values: \(7 > 4\), so result is negative.
Step 3: Subtract the smaller from the larger and attach the negative sign: \[ 7 – 4 = 3 \Rightarrow – (7 – 4) = -3. \]
Answer: \[ -7 + 4 = -3. \]
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Example 3: Evaluate \(-6 + 6\).
Step 1: Rewrite: \[ -6 + 6 = 6 – 6. \]
Step 2: Compare absolute values: \(6 = 6\), so they cancel.
Step 3: Subtract: \[ 6 – 6 = 0. \]
Answer: \[ -6 + 6 = 0. \]
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Example 1: Evaluate \(-3 + 5\).
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Summary (rule to apply every time).
To add a negative and a positive:
- Rewrite as a subtraction: \(-a + b = b – a\).
- Compare absolute values \(a\) and \(b\).
- Subtract the smaller absolute value from the larger.
- The sign of the result is the sign of the number with the larger absolute value; if equal, the result is zero.
FAQs
What is the basic rule for adding a negative and a positive number?
How do I do this on a number line?
What happens if the absolute values are equal?
How is subtraction related to adding a negative?
How do I add several mixed-sign numbers?
How do I handle decimals or fractions?
How can I use absolute value to think about it?
How does this apply to real-life (money/temperature)?
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