Q. \( \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} \)
Answer
\( \left(\frac{1}{2}\right)^6 = \frac{1^6}{2^6} = \frac{1}{64} \)
Detailed Explanation
Compute the product \( \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} \).
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Recognize the repeated multiplication of the same factor. Six factors of \( \frac{1}{2} \) can be written with an exponent:
\[ \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} = \left(\frac{1}{2}\right)^6 \]
Reason: multiplying the same number by itself \( n \) times equals that number to the \( n \)-th power.
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Use the power-of-a-fraction rule: for integers \( a \), \( b \) and positive integer \( n \), \( \left(\frac{a}{b}\right)^n = \frac{a^n}{b^n} \). Apply it here:
\[ \left(\frac{1}{2}\right)^6 = \frac{1^6}{2^6} \]
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Compute numerator and denominator separately:
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Numerator: \( 1^6 = 1 \) because any power of 1 is 1.
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Denominator: compute powers of 2 step by step:
\( 2^2 = 4 \),
\( 2^3 = 8 \),
\( 2^4 = 16 \),
\( 2^5 = 32 \),
\( 2^6 = 64 \).
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Combine the results:
\[ \left(\frac{1}{2}\right)^6 = \frac{1}{64} \]
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Optional: express as a decimal if desired: \( \frac{1}{64} = 0.015625 \).
\( \frac{1}{64} \).
FAQs
What is the value of \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2}?
How can I compute this quickly without multiplying six fractions one by one?
What is the decimal form of \frac{1}{64}?
How does this relate to negative exponents or reciprocals?
Can this be interpreted probabilistically?
How would you generalize multiplying the same fraction n times?
Does the order of multiplication matter here?
If one factor were different, e.g. \frac{1}{2}^5 \times \frac{1}{4}, how to combine?
Math, Calculus, Geometry, etc.