Q. \frac{1}{3} \times \frac{1}{3} \times \frac{1}{3} \times \frac{1}{3} in fraction form

Write the multiplication to be evaluated:

\( \displaystyle \frac{1}{3} \times \frac{1}{3} \times \frac{1}{3} \times \frac{1}{3} \)

Use the rule for multiplying fractions: to multiply fractions, multiply the numerators together and multiply the denominators together. In general,

\( \displaystyle \frac{a}{b} \times \frac{c}{d} = \frac{a \times c}{b \times d} \)

Apply the rule to the first two fractions (multiply numerators and denominators):

\( \displaystyle \frac{1}{3} \times \frac{1}{3} = \frac{1 \times 1}{3 \times 3} = \frac{1}{9} \)

Multiply the result by the third fraction:

\( \displaystyle \frac{1}{9} \times \frac{1}{3} = \frac{1 \times 1}{9 \times 3} = \frac{1}{27} \)

Multiply that result by the fourth fraction:

\( \displaystyle \frac{1}{27} \times \frac{1}{3} = \frac{1 \times 1}{27 \times 3} = \frac{1}{81} \)

Alternatively, recognize repeated multiplication of the same fraction as an exponent:

\( \displaystyle \left(\frac{1}{3}\right)^4 = \frac{1^4}{3^4} = \frac{1}{81} \)

Final answer (fraction form):

\( \displaystyle \frac{1}{81} \)