Q. \[ 2 \times \frac{2}{3} \] as a fraction.
Answer
Multiply the whole number by the numerator: \(2\times\frac{2}{3}=\frac{4}{3}=1\frac{1}{3}\)
Detailed Explanation
Step-by-step solution
- Write the whole number 2 as a fraction with denominator 1: \(2=\frac{2}{1}\). This allows using the fraction multiplication rule.
- Multiply the two fractions by multiplying numerators and multiplying denominators:
\(\displaystyle \frac{2}{1}\times\frac{2}{3}=\frac{2\times 2}{1\times 3}\).
This follows because (a/b)×(c/d) = (a×c)/(b×d). - Compute the products: \(\displaystyle \frac{2\times 2}{1\times 3}=\frac{4}{3}\).
- Simplify if possible. The greatest common divisor of 4 and 3 is 1, so \(\displaystyle \frac{4}{3}\) is already in simplest form.
- Optional: as a mixed number, \(\displaystyle \frac{4}{3}=1\frac{1}{3}\) because 4 divided by 3 is 1 remainder 1.
Final answer (as a fraction): \(\displaystyle \frac{4}{3}\)
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FAQs
What is \(2 \times \frac{2}{3}\) as a fraction?
Multiply: write 2 as \(\frac{2}{1}\). \(\frac{2}{1} \times \frac{2}{3} = \frac{4}{3}\).
How do you multiply a whole number by a fraction?
Convert the whole number to a fraction over 1, then multiply numerators and denominators: \(\frac{a}{1} \times \frac{b}{c} = \frac{ab}{c}\).
Can I use repeated addition to find the product?
Yes. \(2 \times \frac{2}{3} = \frac{2}{3} + \frac{2}{3} = \frac{4}{3}\).
Is \(\frac{4}{3}\) in simplest form?
Yes; \(\gcd(4,3)=1\), so \(\frac{4}{3}\) is fully simplified.
How do I express \(\frac{4}{3}\) as a mixed number?
Divide: \(4 \div 3 = 1\) remainder 1. Mixed form is \(1\frac{1}{3}\).
What is \(\frac{4}{3}\) as a decimal and percent?
What is \(\frac{4}{3}\) as a decimal and percent?
Can I simplify before multiplying (cross-cancellation)?
Yes, but here \(\frac{2}{1} \times \frac{2}{3}\) has no common factors to cancel, so multiply directly to get \(\frac{4}{3}\).
Why is the product greater than \(\frac{2}{3}\)?
Because multiplying by 2 doubles the fraction: \(2 \times \frac{2}{3} =\) twice \(\frac{2}{3}\), giving \(\frac{4}{3}\), which is larger than \(\frac{2}{3}\).
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