Q. \( \frac{1}{3} + \left(-\frac{2}{3}\right) = -\frac{1}{3} \).
Answer
\[
\frac{1}{3}+\left(-\frac{2}{3}\right)=\frac{1+(-2)}{3}=-\frac{1}{3}
\]
Final result: \(-\frac{1}{3}\)
Detailed Explanation
Step-by-step solution
- Write the expression to be evaluated:
\( \frac{1}{3} + \left(-\frac{2}{3}\right) \)
- Note the denominators are the same (3). When adding fractions with the same denominator, keep the denominator and add the numerators:
\( \frac{1}{3} + \left(-\frac{2}{3}\right) = \frac{1 + (-2)}{3} \)
- Compute the numerator. Adding a negative number is the same as subtraction:
\( 1 + (-2) = 1 – 2 = -1 \)
So the fraction becomes
\( \frac{-1}{3} \) - Put the negative sign in conventional form and check for simplification:
\( -\frac{1}{3} \)
The fraction \( \frac{1}{3} \) is already in lowest terms, so no further simplification is possible.
- (Alternative viewpoint) Interpret the original expression as subtraction:
\( \frac{1}{3} + \left(-\frac{2}{3}\right) = \frac{1}{3} – \frac{2}{3} = -\frac{1}{3} \)
Answer: \( -\frac{1}{3} \)
See full solution
Arithmetic FAQs
How do I add \( \frac{1}{3} \) and \( -\frac{2}{3} \)?
Same denominator, add numerators: \(1 + (-2) = -1\), so the sum is \(-\frac{1}{3}\) (already simplified).
Why can I just add the numerators for \( \frac{1}{3} + -\frac{2}{3} \)?.
When denominators match you add numerators with their signs. Here both denominators are \(3\), so add \(1\) and \(-2\) to get \(-1\) over \(3\): \(-\frac{1}{3}\)..
Is \( \frac{1}{3} + -\frac{2}{3} \) the same as \( \frac{1}{3} - \frac{2}{3} \)?
Yes. Adding a negative equals subtracting the positive: \( \frac{1}{3} + -\frac{2}{3} = \frac{1}{3} - \frac{2}{3} = -\frac{1}{3} \)..
How can I see \( \frac{1}{3} + -\frac{2}{3} \) on the number line?
Start at 0, move right \( \frac{1}{3} \), then left \( \frac{2}{3} \). Net movement is left \( \frac{1}{3} \), landing at \( -\frac{1}{3} \)..
How do I check the result with decimals?
Convert: \(\frac{1}{3}=0.333...\), \(-\frac{2}{3}=-0.666...\), sum \(=-0.333...\) which equals \(-\frac{1}{3}...\).
Why is the result negative?
Why is the result negative?
How would I add \(\frac{1}{3}\) and \(-\frac{2}{5}\) (different denominators)?
Find common denominator: convert to fifteenths: \( \frac{1}{3}=\frac{5}{15}, -\frac{2}{5}=-\frac{6}{15}. \) Add: \( \frac{5-6}{15}=-\frac{1}{15}. \)
Is \(-\frac{1}{3}\) in simplest form?
Yes. Numerator 1 and denominator 3 have no common factors other than 1, so \(-\frac{1}{3}\) is fully simplified.
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