Q. Which is the graph of \( f(x) = 2(3)^x \)?
Answer
\( f(x) = 2\cdot 3^{x} \)
Quick explanation:
- \( f(0) = 2 \), \( f(1) = 6 \), \( f(-1) = \tfrac{2}{3} \).
- Horizontal asymptote: \( y = 0 \).
- Strictly increasing exponential growth (base \( 3 > 1 \)), passes through \( (0,2) \) and rises rapidly to the right.
Final result: The graph is an exponential growth curve with y-intercept 2 and horizontal asymptote \( y = 0 \).
Detailed Explanation
Problem
Graph the function \( f(x) = 2 \cdot 3^{x} \).
Step-by-step explanation
-
Recognize the type of function.
The function is an exponential function of the form \( f(x) = a \cdot b^{x} \) with base \( b = 3 \) and vertical scale factor \( a = 2 \). This means it is exponential growth because \( b > 1 \).
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Domain.
Exponential functions are defined for all real inputs. Therefore the domain is
\[ \text{Domain} = (-\infty, \infty). \] -
Range.
For any real \( x \), \( 3^{x} > 0 \). Multiplying by 2 keeps the values positive. Thus
\[ \text{Range} = (0, \infty). \] -
Horizontal asymptote.
As \( x \) becomes very negative, \( 3^{x} \) approaches 0. Multiplying by 2 still approaches 0, so the horizontal asymptote is
\[ y = 0. \] -
Intercepts.
Compute the y-intercept by evaluating at \( x = 0 \):
\[ f(0) = 2 \cdot 3^{0} = 2 \cdot 1 = 2. \]
So the graph passes through \( (0,2) \).There is no x-intercept because \( f(x) > 0 \) for all \( x \), so the graph never crosses the x-axis.
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Monotonicity (increasing/decreasing).
Differentiate to check the slope:
\[ f'(x) = 2 \cdot 3^{x} \cdot \ln 3. \]
Since \( 2 > 0 \), \( 3^{x} > 0 \), and \( \ln 3 > 0 \), we have \( f'(x) > 0 \) for all \( x \). Therefore the function is strictly increasing on its entire domain. -
Concavity.
Compute the second derivative:
\[ f”(x) = 2 \cdot 3^{x} \cdot (\ln 3)^{2}. \]
This is positive for all \( x \), so the graph is concave upward everywhere. -
Key points to plot.
Compute a small table of values to guide the sketch.
x f(x) = 2 · 3^x -2 \( f(-2) = 2 \cdot 3^{-2} = 2 \cdot \tfrac{1}{9} = \tfrac{2}{9} \approx 0.222\) -1 \( f(-1) = 2 \cdot 3^{-1} = 2 \cdot \tfrac{1}{3} = \tfrac{2}{3} \approx 0.667\) 0 \( f(0) = 2 \) 1 \( f(1) = 2 \cdot 3 = 6 \) 2 \( f(2) = 2 \cdot 9 = 18 \) Plot these points and draw a smooth curve through them that is increasing and concave up, approaching the line \( y = 0 \) on the left.
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Transformation description.
Start with the basic graph of \( y = 3^{x} \), which has y-intercept 1 and horizontal asymptote \( y = 0 \). Multiplying by 2 produces a vertical stretch by factor 2. This doubles all y-values, so the y-intercept moves from \( (0,1) \) to \( (0,2) \), and other y-values are doubled accordingly.
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Final sketch description.
The graph of \( f(x) = 2 \cdot 3^{x} \) is an increasing exponential curve that:
- has domain \( (-\infty,\infty) \),
- has range \( (0,\infty) \),
- has horizontal asymptote \( y = 0 \),
- passes through \( (0,2) \), \( (1,6) \), \( (-1,\tfrac{2}{3}) \),
- is strictly increasing and concave up.
When sketched, the curve lies very close to the x-axis for large negative x, crosses the y-axis at 2, and then rises rapidly for positive x.
Graph
FAQs
What type of function is f(x) = 2 \cdot 3^x?
What is the domain and range of f(x) = 2 \cdot 3^x?
What is the horizontal asymptote?
What are the x- and y-intercepts?
Is the function exponential growth or decay?
How do I sketch the graph quickly?
What is the inverse function?
How does f(x) relate to g(x) = 3^x (what transformation)?
How do I evaluate f(x) for non-integer x?
Where is f(x) increasing or decreasing?
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