Q. Which is the graph of \( y – 3 = x + 6 \)
Answer
Start with the equation
\[ y – 3 = x + 6 \]
Add 3 to both sides to obtain
\[ y = x + 9 \]
This is the equation of a straight line with slope \(1\) and y-intercept \(9\). Its y-intercept is the point \( (0,9) \). The x-intercept is found by setting \(y=0\), giving \(0 = x + 9\) and hence the point \( (-9,0) \). The point \( (-6,3) \) also lies on the line since \( -6 + 9 = 3 \).
Final form:
\[\boxed{y = x + 9}\]
Detailed Explanation
Problem: Write the equation \( y – 3 = x + 6 \) in slope-intercept form and find the slope, the x- and y-intercepts, and describe the graph.
Step 1 — Start with the given equation
\[
y – 3 = x + 6
\]
Step 2 — Isolate \(y\) to obtain slope-intercept form
Add \(3\) to both sides:
\[
y – 3 + 3 = x + 6 + 3
\]
which simplifies to
\[
y = x + 9
\]
This is in the form \(y = mx + b\).
Step 3 — Determine the slope
Compare \(y = x + 9\) with \(y = mx + b\). The coefficient of \(x\) is
\[
m = 1.
\]
Step 4 — Find the y-intercept
Set \(x = 0\):
\[
y = 0 + 9 = 9,
\]
so the y-intercept is the point \((0,\,9)\).
Step 5 — Find the x-intercept
Set \(y = 0\):
\[
0 = x + 9
\]
which gives
\[
x = -9,
\]
so the x-intercept is the point \((-9,\,0)\).
Step 6 — Describe the graph
The graph is a straight line with slope \(1\) passing through the points \((0,\,9)\) and \((-9,\,0)\).
Answer
\[
y = x + 9,\quad m = 1,\quad \text{x-intercept }(-9,\,0),\quad \text{y-intercept }(0,\,9)
\]
Graph
FAQs
What is the graph of (y-3=(x+6))?
How do I rewrite (y-3=(x+6)) in slope-intercept form?
What are the slope and y-intercept?
What are the x- and y-intercepts of the line?
Which points should I plot to draw the line?
Is (y-3=(x+6)) already in point-slope form?
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What are the domain and range of this line?
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