Q. Which is the graph of \( y – 3 = x + 6 \)

Answer

Start with the equation
\[ y – 3 = x + 6 \]

Add 3 to both sides to obtain
\[ y = x + 9 \]

This is the equation of a straight line with slope \(1\) and y-intercept \(9\). Its y-intercept is the point \( (0,9) \). The x-intercept is found by setting \(y=0\), giving \(0 = x + 9\) and hence the point \( (-9,0) \). The point \( (-6,3) \) also lies on the line since \( -6 + 9 = 3 \).

Final form:
\[\boxed{y = x + 9}\]

Detailed Explanation

Problem: Write the equation \( y – 3 = x + 6 \) in slope-intercept form and find the slope, the x- and y-intercepts, and describe the graph.

Step 1 — Start with the given equation

\[
y – 3 = x + 6
\]

Step 2 — Isolate \(y\) to obtain slope-intercept form

Add \(3\) to both sides:

\[
y – 3 + 3 = x + 6 + 3
\]

which simplifies to

\[
y = x + 9
\]

This is in the form \(y = mx + b\).

Step 3 — Determine the slope

Compare \(y = x + 9\) with \(y = mx + b\). The coefficient of \(x\) is

\[
m = 1.
\]

Step 4 — Find the y-intercept

Set \(x = 0\):

\[
y = 0 + 9 = 9,
\]

so the y-intercept is the point \((0,\,9)\).

Step 5 — Find the x-intercept

Set \(y = 0\):

\[
0 = x + 9
\]

which gives

\[
x = -9,
\]

so the x-intercept is the point \((-9,\,0)\).

Step 6 — Describe the graph

The graph is a straight line with slope \(1\) passing through the points \((0,\,9)\) and \((-9,\,0)\).

Answer

\[
y = x + 9,\quad m = 1,\quad \text{x-intercept }(-9,\,0),\quad \text{y-intercept }(0,\,9)
\]

See full solution

Graph

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FAQs

What is the graph of (y-3=(x+6))?

A straight line with slope 1 passing through ((-6,3)). In slope-intercept form it is (y=x+9), so y-intercept is 9.

How do I rewrite (y-3=(x+6)) in slope-intercept form?

Solve for y: (y-3=x+6) so (y=x+9).

What are the slope and y-intercept?

Slope (m=1). Y-intercept (b=9), point ((0,9)).

What are the x- and y-intercepts of the line?

Set (y=0): (0=x+9) so x-intercept ((-9,0)). Y-intercept is ((0,9)).

Which points should I plot to draw the line?

Plot ((-6,3)) (given point), ((0,9)) (y-intercept), and ((-9,0)) (x-intercept). Connect them straight.

Is (y-3=(x+6)) already in point-slope form?

Yes: point-slope is (y-y_1=m(x-x_1)). Here (m=1) and ((x_1,y_1)=(-6,3)).

What is the standard form of the equation?

Rearranged: (x-y+9=0) (equivalently (x-y=-9)).

What are the domain and range of this line?

Both domain and range are all real numbers, ( (-infty,infty) ).
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